Can someone help me with triangulation in trigonometry?

How much is left in your account at the end of the week?

Strike441 [17]

Answer:

c. $345.94

Step-by-step explanation:

298.72+425.69= 724. 41

724.41-29.72-135.47-208.28= 350.94

350.94-5 = 345.94

6 0

3 years ago

A rock thrown vertically upward from the surface of the moon at a velocity of 36m/sec reaches a height of s = 36t - 0.8 t^2 met

Verdich [7]

Answer:

a. The rock's velocity is $v(t)=36-1.6t \:{(m/s)}$ and the acceleration is $a(t)=-1.6 \:{(m/s^2)}$

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

Velocity is defined as the rate of change of position or the rate of displacement. $v(t)=\frac{ds}{dt}$
Acceleration is defined as the rate of change of velocity. $a(t)=\frac{dv}{dt}$

a.

The rock's velocity is the derivative of the height function $s(t) = 36t - 0.8 t^2$

$v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t$

The rock's acceleration is the derivative of the velocity function $v(t)=36-1.6t$

$a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6$

b. The rock will reach its highest point when the velocity becomes zero.

$v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5$

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

$s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405$

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = $\frac{405}{2} =202.5 \:m$

To find the time it reach half its maximum height, we need to solve

$36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41$

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

$36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45$

The rock is aloft for 45 seconds.

5 0

4 years ago

Please help me slove this problem <br> -6x + 4 = -20

Yakvenalex [24]

Positive 4 is the answer! Hope this helps!

7 0

3 years ago

Read 2 more answers

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

frosja888 [35]

Answer:

7x + 2y = 1

Step-by-step explanation:

1. Find the slope of the line.

(y2-y1)/(x2-x1) ----> (11 - (-3))/((-3) -1) ----> (11+3)/ (-3 -1) ----> 14/-4

*lets simplify into (7/-2)*

2. Write into slope intercept form.

y=mx+b (m is the slope) (b is the y intercept)

y = (7/-2)x + b

We now need to find the value of b, this can be done by plugging in values of x and y, and using algebra to solve.

11 = (7/-2)(-3) + b

11 = 10.5 + b

b = 0.5 or 1/2

slope intercept form y = (7/-2)x + 1/2

Now we convert to standard form: ax+by=c

*In this form we our a term cannot be a fraction nor can it be negative*

1. Get x and y on the same side, and since our x term is negative right now, we can make it positive by adding it on both sides.

(7/2)x + y = 1/2

2. We now want to get rid of the fraction in term a, so we multiply the entire function by two, so the denominator cancels out.

2(7/2)x + 2y = 2(1/2)

Simplify and you get

7x + 2y = 1

6 0

3 years ago

Find the slope of the line through the points<br> (3, 4) and (5, 7).

Alekssandra [29.7K]

The slope is the change in Y over the change in X.

Slope = (7-4) / (5-3)

Slope = 3/2

3 0

4 years ago