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just olya [345]
1 year ago
11

The radius of Circle L is 3m. The length and width of Rectangle M is 12m and 18m, respectively. If Point P will be randomly plac

ed on the image below, what is the probability that the point will be placed within Circle L. Use 3 for Pi in this problem.

Mathematics
1 answer:
Roman55 [17]1 year ago
5 0

To get the probability of Point P be placed within the circle L, we need to get the ratio between the area covered by the circle and the area covered by the rectangle.

The area of the circle is:

undefined

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Without solving, NO SOLUTION describes which equation?
CaHeK987 [17]

Answer:

The equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

Step-by-step explanation:

a)

6a = 9a

subtract 9a from both sides

6a - 9a = 9a - 9a

-3a = 0

divide both sides by -3

-3a / -3 = 0/-3

Simplify

a = 0

b)

5x = 28

divide both sides by 5

5x/5 = 28/5

x = 28/5

c)

y = y + 1

subtract y from both sides

y - y = y+1-y

0 = 1

These sides are not equal, so

NO SOLUTION!

d)

y + 5 = 12

subtract 5 from both sides

y + 5 - 5 = 12 - 5

y = 7

Conclusion:

Therefore, the equation 'y = y + 1' represents NO SOLUTION.

Hence, option 'C' is true.

5 0
3 years ago
Read 2 more answers
Plz Help me
Dafna1 [17]

Answer:

6/0

Step-by-step explanation:

Step 1: Label your x and y's

(0,-11) (0, 5)

x1 y1  x2 y2

Step 2: Plug in your x1, x2, y1, and y2 into the slope formula

The slope formula is y1 -y2/ x1 - x2

-5-(-11)/ 0 = 6/0

Undefined

6 0
3 years ago
The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
NikAS [45]

Answer:

I think it's C, x-y-8=0

Step-by-step explanation:

5 0
3 years ago
On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to
Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = (21-11) \ million = 10 million

1960-1970 = (41-21)\ million = 20 million

1970-1980 = (71-41)\ million = 30 million

1980-2000 = (161-71)\ million= 90 million

Rate of change (1950-1960)= \frac{10}{11} \times 100= 90.90\%

Rate of change (1960-1970) = \frac{20}{21} \times 100= 95.23\%

Rate of change (1970-1980)=  \frac{30}{41} \times 100= 73.17\%

Rate of change (1980-2000)= \frac{90}{71} \times 100= 126.76\%

∴ rate of change between 1980 to 2000 is 126.78%

7 0
3 years ago
I need a 30 x axes and 30 y axes graph single quadrant graph please.<br><br><br> BRAINLYIST REWARDED
kvv77 [185]

Yes, because the ratios are equivalent between each pair of values.

6 0
2 years ago
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