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pychu [463]
3 years ago
5

Is line e perpendicular to line g?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

Yes.

Step-by-step explanation:

Always.

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Write each decimal using a negative exponent.
leonid [27]

Answer:

The answer to your question is below

Step-by-step explanation:

When using scientific notation,

- when we move the decimal point to the right, the power will be negative.

- when we move the decimal point to the left, the power will be positive.

a) 0.00001    move the decimal point 5 places to the right   1 x 10⁻⁵

b) 0.001         move the decimal point 3 places to the right   1 x 10⁻³

8 0
3 years ago
Read 2 more answers
A boat can travel 64 miles on 7 gallons of gasoline. How much gasoline will it need to go 24 miles?
Oksanka [162]

Answer:192

Step-by-step explanation:

5 0
3 years ago
Given: m∠A = m∠C = 90° AB ║ DC Prove: ∆ABD ≅ ∆CBD
Genrish500 [490]

Answer:

Angle-Angle-Side (AAS)

Step-by-step explanation:

Given triangles; ΔABD and ΔCBD

  <A = <C = 90^{0} (right angle property)

   AB ║ DC (given)

Then,

    DA ║ CB

   <B ≅ <D (congruent property)

    DB ≅ BD (similarity property)

    <D + <B = <B + <D (complementary angles, and property of triangles)

Therefore by Angle-Angle-Side (AAS),

                 ∆ABD ≅ ∆CBD

4 0
2 years ago
Simplify the expression
ollegr [7]

Answer:

<h3>              f(x) = x - 6</h3><h3>             g(x) = x - 5</h3>

Step-by-step explanation:

\dfrac{x^2-8x+12}{x^2-7x+10}\\\\x^2-7x+10\ne0\ \iff\ x=\frac{7\pm\sqrt{49-40}}{2}\ne0\ \iff\ x\ne5\ \wedge\ x\ne2\\\\\\\dfrac{x^2-8x+12}{x^2-7x+10}=\dfrac{x^2-2x-6x+12}{x^2-2x-5x+10}=\dfrac{x(x-2)-6(x-2)}{x(x-2)-5(x-2)}=\\\\\\ =\dfrac{(x-2)(x-6)}{(x-2)(x-5)}=\dfrac{x-6}{x-5}\\\\\\f(x)=x-6\\\\g(x)=x-5

4 0
3 years ago
Pine Bluff Middle School is having its annual Spring Fling dance, which will cost
Anon25 [30]
I think your asking  how much the school will have left over. If so:

125 ( not including the tickets)
It depends on how many kids are coming to the dance in order to fully solve this problem.

You didn't word this properly so that what I got with what I had:)

If you have anymore questions, ask me them on my profile so I'll be sure to get them:)

I hope this helps:)
3 0
3 years ago
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