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3 years ago

Which quantitiy can be described as changing at a constant rate?

Mathematics

1 answer:

Agata [3.3K]3 years ago

4 0

Answer:a

Step-by-step explanation:

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(40 POINTS)

Y_Kistochka [10]

Answer:

1. f(0) = 501170

2. decreasing

3. 2% decrease

4. 302438

Step-by-step explanation:

In 1995 x=0

f(x) = 501170(0.98)^0

f(0) = 501170

The population is decreasing since we are multiplying by .98 ^x

.98 is less than 1 so it is getting smaller each time.

1 -.98 = .02

It is decreasing by 2 % each year

2020-1995 =25 years

f(25) = 501170(0.98)^25

=302438.41862

Rounding to the nearest whole number

302438

7 0

4 years ago

3x-y=2 whats the X and Y

slamgirl [31]

3x-y-2=0 that’s the answer to this question

6 0

3 years ago

The chart :

Misha Larkins [42]

Let x be the number of 30 days.

(a) 65 - 2.5x = 55 - 2x

(b) 65 - 2.5x = 55 - 2x
65 - 55 = 2.5x - 2x
0.5x = 10
x = 20
Therefore, each card will result in the value of $15 when they have equal value.

3 0

3 years ago

Read 2 more answers

A right triangle whose hypotenuse is StartRoot 18 EndRoot18 m long is revolved about one of its legs to generate a right circula

skelet666 [1.2K]

Answer:

V = $\frac{1}{3}$ π(8 - $\frac{8}{3}$ ) $\sqrt{\frac{8}{3} }$ = 9.11 $m^{3}$

r = 4 $\frac{\sqrt{3} }{3}$

h = $\sqrt{\frac{8}{3} }$

Step-by-step explanation:

Given that the right triangle whose hypotenuse is $\sqrt{8}$

Let r is the radius of the cone
Let h is the height of the cone

We know that:

$r^{2} + h^{2} = 8$

<=> $r^{2} = 8 - h^{2}$

The volume of the cone is:

V = π $r^{2} \frac{1}{3} h$

<=> V = π $\frac{1}{3}(8 - h^{2} )h$

Differentiate w.r.t h

$\frac{dV}{dh}$ = π $\frac{1}{3}$ (8 - $3h^{2}$ )

For maximum/minimum: $\frac{dV}{dh}$ = 0

<=> π $\frac{1}{3}$ (8 - $3h^{2}$ ) = 0

<=> $h^{2}$ = $\frac{8}{3}$

<=> h = $\sqrt{\frac{8}{3} }$

=> $r^{2}$ = $\frac{16}{3}$

<=> r = 4 $\frac{\sqrt{3} }{3}$

So the volume of the cone is:

V = $\frac{1}{3}$ π(8 - $\frac{8}{3}$ ) $\sqrt{\frac{8}{3} }$ = 9.11 $m^{3}$

6 0

3 years ago

How to find the permimeter of triangle ABC with the vertices of A(1,1) B(7,1) C(1,9)

Lady bird [3.3K]

Answer:

Perimeter of the triangle=24 units

Step-by-step explanation:

The given vertices of the triangle ABC are A(1,1), B(7,1) and C(1,9).In order to fin the perimeter, we need to find the lengths of the triangle.

Thus, AB= $\sqrt{(7-1)^{2}+(1-1)^{2}}=\sqrt{36}=6$ ,

BC= $\sqrt{(1-7)^{2}+(9-1)^{2}}=\sqrt{36+64}=\sqrt{100}=10$ and

AC= $\sqrt{(1-1)^{2}+(9-1)^{2}}=\sqrt{64}=8$

Now, Perimeter of the triangle= Sum of all the sides

=AB+BC+AC

=6+10+8

=24 units.

Thus, Perimeter of the triangle=24 units

5 0

3 years ago