Answer:
1/2
Step-by-step explanation:
We can find the slope given two points by
m = (y2-y1)/(x2-x1)
= (9-5)/ (18-10)
= 4/8
= 1/2
For the first part, the answer is choice B) 360. This applies to any polygon and it doesn't have to be an octagon. The sum of the exterior angles of any polygon is always 360 degrees. This is something you should memorize or have on a reference sheet.
For the second part, the answer is choice C) 142 degrees. We have a parallelogram (specifically a rhombus but that doesn't matter) so the adjacent angles are supplementary. This means they add to 180 degrees. Solving x+38 = 180 leads to x = 142
Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.
3÷?=36
multiply both sides by 3 to figure out what "?" is
36*3=108
3÷108=36
?=108
First, you formulate a ratio of Audrey's work time to work done. In this case, 3/5 hour : 2/5 square yards. Expressing and simplifying that into a fraction would yield:
3/5 ÷ 2/5 = 3/5 * 5/2 = 3/2
We use this ratio to determine the sq yards she could paint in an hour:
1 hour * (1/(3/2) = 2/3 square yards
I hope I was able to help you with this question. Have a good day.
