Answer: The answer is
Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.
Let, AC = 3x and CM = 4x.
In the right-angled triangle ACM, we have
Now,
Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.
So,
Comparing equations (A) and (B), we have
Thus,
The tension in the cable is given by the newton's first law will be 163.622 N.
<h3>What is newton's first law?</h3>The summation of the force is equal to zero.
The formula is given as
ΣF = 0
Where m is the mass of the body and a is the acceleration.
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam.
Then the tension in the cable will be
Let T be the tension in the cable.
T sin 29° + T sin 53° – 210 = 0
On simplifying, we have
T (sin 29° + sin 53°) = 210
T = 163.622 N
More about the newton's first law link is given below.
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