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elena-14-01-66 [18.8K]
4 years ago
5

PLEASE HELP ASAP

Mathematics
1 answer:
Ulleksa [173]4 years ago
5 0

Answer:

option 3.

(ƒ • g)(x) = x3 – 3x2 + 2x – 6

Step-by-step explanation:

ƒ(x) = x2 + 2

g(x) = x – 3

if we look at the functions they are multiplying, so we have to multiply the equivalents to the functions among themselves

(ƒ • g)(x) = (x2 + 2) • ( x - 3)

(ƒ • g)(x) = (x2 * x) + (x2 * -3) + ( 2 * x) + (2 * -3)

(ƒ • g)(x) = (x3) + (-3x2) + (2x) + (-6)

(ƒ • g)(x) = x3 - 3x2 + 2x - 6

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Read 2 more answers
Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confide
ioda

Answer:

The question is incomplete, but the step-by-step procedures are given to solve the question.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{\sigma}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M.

The upper end of the interval is the sample mean added to M.

The 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (lower end, upper end).

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