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4 years ago

PLEASE HELP ASAP

Mathematics

1 answer:

Ulleksa [173]4 years ago

5 0

Answer:

option 3.

(ƒ • g)(x) = x3 – 3x2 + 2x – 6

Step-by-step explanation:

ƒ(x) = x2 + 2

g(x) = x – 3

if we look at the functions they are multiplying, so we have to multiply the equivalents to the functions among themselves

(ƒ • g)(x) = (x2 + 2) • ( x - 3)

(ƒ • g)(x) = (x2 * x) + (x2 * -3) + ( 2 * x) + (2 * -3)

(ƒ • g)(x) = (x3) + (-3x2) + (2x) + (-6)

(ƒ • g)(x) = x3 - 3x2 + 2x - 6

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3 years ago

in a game of tug of war your team changes -1 3/10 feet in position every 10 seconds. What is your change in position after 30 se

Harman [31]

Answer:

Change in position after 30 seconds will be $- \frac{26}{10}$

Step-by-step explanation:

Given:

Change on position in every 10 seconds = $-1 \frac{3}{10}$

To Find:

Change in position after 30 seconds = ?

Solution:

For every 10 seconds the team changes a distance of $-1 \frac{3}{10}$ feet

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The change in position will be $-1 \frac{3}{10}$ feet = $-\frac{13}{10}$

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3 years ago

Joe has 45 minutes before he has to go to soccer practice he spends 20 minuets eating a snack and the rest of the time doing his

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4 years ago

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scoundrel [369]

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3 years ago

An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2 : Suppose a sample of

rewona [7]

Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.

333 - 257 = 76 have spills.

This means that $n = 333, \pi = \frac{76}{333} = 0.228$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 - 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.199$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 + 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.257$

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

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3 years ago