Assuming this is the equation you want to operate on:



Before final operation we have to assume that x is not equal to 0. :)
Answer:
4 5/2
Step-by-step explanation:
1/4
x 2 =12/8
12/8
x 33/4 =45/2
the answers are pretty easy to answer but it can be a little bit hard.
Answer:The slopw is -1/2
Step-by-step explanation
A slope that is a opposite reciprocal of another slope is always perpendicular. Make sure it is a opposite reciprocal. Not just a regular reciprocal.
<span>No, because postulates are assumptions. Some true, some not. So it can't be used to prove it</span>