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grandymaker [24]
2 years ago
11

an entertainment firm offers several DJ choices and light show that range in price based on the rental time period. the DJ's cos

t between $219.00 and $369.00 per night and the night show cost between $159.00 and $309.00 per night. if you are booking both a DJ and a night show, write a compound and inequality that represent the possible total amount you would pay, x.
Mathematics
1 answer:
Mnenie [13.5K]2 years ago
4 0

Answer:

219 + 159 <= x <= 369 + 309

378 <= x <= 678

Step-by-step explanation:

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Shorty’s Muffler advertises it can install a new muffler in 30 minutes or less. However, the work standards department at corpor
pav-90 [236]

Answer:

The installations at the Maumee branch would you expect to take more than 30 minutes is 10.

Step-by-step explanation:

Consider the provided information.

Let x is the installations at the Maumee branch take more than 30 minutes.

The work standards department at corporate headquarters recently conducted a study and found that 20% of the mufflers were not installed in 30 minutes or less.

Therefore, π=0.20

The Maumee branch installed 50 mufflers last month.

Thus, n=50

Mean of the distribution: μ=nπ

Substitute the respective values in the above formula.

μ=(50)(0.20)

μ=10

Hence, the installations at the Maumee branch would you expect to take more than 30 minutes is 10.

7 0
3 years ago
jennifer is shopping with her mother they pay $2 per pound for tomatoes at the vegetable stand. find the constant of proportiona
Tresset [83]
One the first problem on finding the constant of <span> proportionality in this situation the answer is 2. Below is the solution:

constant = unit rate
unit rate = $2/ poung 
K = 2

For the second question, the equation is the below:

T = 2p or y = 2x</span>
3 0
3 years ago
Read 2 more answers
Which of the following is most likely the next step in the series?
lilavasa [31]

Answer:

B

Step-by-step explanation:

Hi there!

TL;DR: Observe the vertices of the shapes inside the circles and their relationship with the circle.

For the first figure, the rectangle has 4 vertices and there are 4 dots on the perimeter of the circle.

For the second figure, the triangle has 3 vertices and there are 3 dots on the perimeter of the circle.

For the third figure, the line has 2 points and there are 2 dots on the perimeter of the circle.

For the fourth figure, there would most likely be only one dot on the perimeter of the circle (4, 3, 2, 1). The only option that shows this is B.

I hope this helps!

3 0
2 years ago
You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
Which of the following statements is likely to be true?
Nostrana [21]

Answer:

c. The interquartile range offers a measure of income inequality among California residents.

Step-by-step explanation:

The range is the midspread which measures statistical dispersion. This is also known as H-spread which is equal to the difference between 75th percentile and 25th percentile. In the given scenario the interquartile range offers measure of income inequality among California residents.

5 0
3 years ago
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