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Temka [501]
3 years ago
7

Stan, a local delivery driver is paid $3.50 per mile driven plus a daily amount of $75. On Monday he is assigned a route that is

30 miles longer. How much is he being paid for that day? Independent and dependent variables?
Mathematics
1 answer:
Maurinko [17]3 years ago
4 0
3.50m+75 for the 30 miles, he is being paid 105 plus the daily amount of 75 which equals to 180$.
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Two minor league baseball players got a total of 210 hits. Washington had 12 more hits than Sanchez. find the number of hits fro
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Washington: 117 Hits
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A plot of 1/no2 versus time is linear. using this information, identify the factor by which the rate will increase in model (c)
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This is hard in mathematical language, but there is only this way to present it. Let us denote by A the consentration of the substance and by A' its rate.
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3 years ago
Use the Distance Formula to find the distance to the nearest tenth between A(-7, -4) and B(-2, 0).
goldenfox [79]
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√[(x'-x)^2+(y'-y)^2]
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8 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
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