Hence, the value of x=8
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This is hard in mathematical language, but there is only this way to present it. Let us denote by A the consentration of the substance and by A' its rate.
We have that b/A= t+c where c is a constant.
Hence A=b/(c+t)
By differentiating, we get that A'=-b/(C+t)^2
Then, we have that -(A)^2=A'/b
Hence at any point, we have that if we make the concentration 17 times, we have that there is a 17 times bigger , the rate will become bigger by 17*17, hence 289 times faster.
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41
the distance is approximately 6.4 units
Answer:

Step-by-step explanation:
The standard equation of a horizontal hyperbola with center (h,k) is

The given hyperbola has vertices at (–10, 6) and (4, 6).
The length of its major axis is
.



The center is the midpoint of the vertices (–10, 6) and (4, 6).
The center is 
We need to use the relation
to find
.
The c-value is the distance from the center (-3,6) to one of the foci (6,6)





We substitute these values into the standard equation of the hyperbola to obtain:

