0, the slope and y-intercept is 0
V= 3 x 4^2 x 12
v= 576cm^3
Answer:
11,880π in^3
Step-by-step explanation:
The volume of a cylinder = π r^2 h
Large Cylinder V = π * 15^2*40 = 9,000π in^3
Small Cylinder V = π * 12^2 * (60-40) = 2880π in^3
Adding: the total volume of the model = 11,880π in^3
Yes. That point is in the solution space.
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You can also figure out algebraically whether the point satisfies the inequality
y < 2x + 10
Substitute the numbers
3 < 2·2 + 10
3 < 14 . . . . . . . . . . . True. (2, 3) is a solution