Question

I. The airport branch of a car rental company maintains a fleet of 50 SUVs. The interarrival time between requests for an SUV is 2.4 hours, on average, with a standard deviation of 2.4 hours. There is no indication of a systematic arrival patterns over the course of a day. Assume that, if all SUVs are rented, customers are willing to wait until there is an SUV available. An SUV is rented, on average, for 3 days, with a standard deviation of 1 day. a) What is the average number of SUVs parked in the company's lot

Answer 1

Answer:

20

Step-by-step explanation:

For the computation of the average number of SUVs parked in the company's lot first it is required to compute the utilization which is shown below:-

$Utilization = \frac{p}{a\times m}$

where p indicates activity time which is equal to 3 days = 72 hours

a indicates an interarrival time which is equal to 2.4

m indicates the number of servers which is equal to 50

now we will put the values into the above formula

$Utilization = \frac{72}{2.4\times 50}$

After solving the above equation we will get

u = 0.6

or

60%

now, the average cars parked in the company's lot is

$Average\ cars = 50 - 60\%\times 50$

= 50 - 30

= 20