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2 years ago

The sum of two numbers is 47. one of the numbers is 2 more than twice the other number. find the value of the smaller number.

1 answer:

4 0

X + y = 47
x = 2y + 2

2y + 2 + y = 47
3y + 2 = 47
3y = 47 - 2
3y = 45
y = 45/3
y = 15

x = 2y + 2
x = 2(15) + 2
x = 30 + 2
x = 32

ur numbers are 15 and 32

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2 years ago

Fidn the points of intersection

Sedbober [7]

EQ. 1: x + y = 8

EQ. 2: 4x-y = 7

Rewrite EQ. 1 as EQ. 3: x = 8-y

Replace x in EQ.2 with EQ. 3:

4(8-y) - y = 7

Use the distributive property:

32 - 4y - y = 7

Combine like terms:

32 - 5y = 7

Subtract 32 from each side:

-5y = -25

Divide both sides by -5

y = -25 / -5

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2 years ago

A ball is drawn at random from a box containing 12 red,18

Lubov Fominskaja [6]

Answer:

For a: The probability of getting a red or blue ball is 0.48

For b: The probability of getting a white, blue or orange ball is 0.81

For c: The probability of getting neither white or orange ball is 0.48

Step-by-step explanation:

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}$ .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

For a:

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48$

For b:

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81$

For c:

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52$

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

7 0

2 years ago

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liq [111]

Answer:

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Step-by-step explanation:

Because you start with 10, you will always have a 0 at the end.

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2 years ago

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Compute the probability of drawing two clubs from a standard deck of 52 cards. Round your answer to four decimal places. Answer:

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It’s 110 because you add two 52

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