The sum of two numbers is 47. one of the numbers is 2 more than twice the other number. find the value of the smaller number.

1 answer:

4 0

X + y = 47
x = 2y + 2

2y + 2 + y = 47
3y + 2 = 47
3y = 47 - 2
3y = 45
y = 45/3
y = 15

x = 2y + 2
x = 2(15) + 2
x = 30 + 2
x = 32

ur numbers are 15 and 32

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