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Inessa05 [86]
3 years ago
9

A line with a slope of -8 passes through the points (6,-1) and (w, 7). What is the value of w?

Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0

Answer:

The value of w is 5.

Step-by-step explanation:

To find the value of w, we start with the slope equation. Then, we input all of the values we are given.

m(slope) = (y2 - y1)/(x2 - x1)

-8 = (7 - -1)/(w - 6)

-8 = 8/(w - 6)

Now to solve for w, we need to cross multiply.

-8(w - 6) = 8

w - 6 = -1

w = 5

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Eric has two number cubes each labeled 1 to 6. Eric is going to conduct an experiment by tossing the cubes a total of 180 times.
Lera25 [3.4K]
The possible outcomes are:
1,1~~1,2~~1,3~~1,4~~1,5~~1,6
2,1~~2,2~~2,3~~2,4~~2,5~~2,6
3,1~~3,2~~3,3~~3,4~~3,5~~3,6
4,1~~4,2~~4,3~~4,4~~4,5~~4,6
5,1~~5,2~~5,3~~5,4~~5,5~~5,6
6,1~~6,2~~6,3~~6,4~~6,5~~6,6

The possible products are:
1~~2~~3~~4~~5~~6
2~~4~~6~~8~~10~~12
3~~6~~9~~12~~15~~18
4~~8~~12~~16~~20~~24
5~~10~~15~~20~~25~~30
6~~12~~18~~24~~30~~36


a) There are 36 outcomes.

b) 5/36 * 180 = 25

c) 6/36 * 180 = 30

d) 16/36 * 180 = 80

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3 years ago
What function is a quadratic function
Nikolay [14]
The answer is d or the last one
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3 years ago
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the price of a car was reduced to 25% off the car is now £14.625 work out what the car was before it was reduced
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2 years ago
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



5 0
3 years ago
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Can somebody please explain question (i) and (ii) to me​
yuradex [85]
<h2>♨ANSWER♥</h2>

hey buddy, if u attach your question to this we can help you to find an answer for your question.

<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>

_♡_<em>mashi</em>_♡_

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