Answer:
Times, and conquer.
Step-by-step explanation:
First half the picture, for the circle and square. so we know the base is 28m, and the length including the circle is 24. So now times the two numbers and bam your answer.
Answer:
1024
Step-by-step explanation:
n(10) =2^10
n(10) = 1024
Answer:
9) VU = 15
SU = 21.21
TV = 21.21
SW = 10.61
10) OM = 46
PN = 23
ON = 46
MN = 46
Step-by-step explanation:
9) SU = TV = √15²+15² = 21.21
SW = 21.21/2 = 10.61
10) PN = 46/2 = 23
Answer:
Step-by-step explanation:
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Answer:
8
Step-by-step explanation:
Key to this question is assume that each exchange preserves the total dollar amount of Nick’s money.
If He exchanges all his $5 bills for $1 bills, it means that a $5 bill will result in 5 $1 bills as such, if he had x number of $5 bill, after the exchange, he would have 5x $1 bills.
then all his $20 bills for $5 bills, it means that for each $20 bill, he gets 4 $5 bills which means that if he had y number of $5 bills, after the exchange, he would have 4y $5 bills.
and finally all his $100 bills for $20 bills, then he must have received 5 $20 bills for each $100 such that if he had z number of $100 bills before the exchange, he would have 5z number of $20 bills after the exchange. Given that originally he had 17 bills and later 77 bills then
x + y + z = 17
5x + 4y + 5z = 77
Multiplying the first equation by 5,
5x + 5y + 5z = 85
5x + 4y + 5z = 77
subtract 2 from 1
y = 8
