The height of the antenna on the roof of the local building is approximately 8 meters.
The situation forms a right angle triangle.
<h3>Properties of a right angle triangle:</h3>
- One of its angles is equals to 90 degrees
- The sides of the triangles can be calculated using Pythagoras theorem.
Therefore, let's find the height of the building and the radio antenna from the eye point.
Using trigonometric ratios,
tan 40° = opposite / adjacent
tan 40° = x / 25
where
x = the height of the building and the radio antenna from the eye point.
x = 25 tan 40
x = 25 × 0.83909963117
x = 20.9774907794 meters
Let's find the height of the building from his eye point.
tan 28° = y / 25
where
y = height of the building from his eye point
y = 25 × tan 28°
y = 25 × 0.53170943166
y = 13.2927357915 meters
Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786
Height of the antenna ≈ 8 meters
learn more on elevation here: brainly.com/question/17582385?referrer=searchResults
With the mean and range, we can estimate the weights of the smallest and largest animals in each group.
For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]
<h3>
Which conclusions can be made with the given information?</h3>
We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.
- From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
- And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg
(Assuming a normal distribution).
Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:
- The largest dog weights 32kg + 45kg/2 = 54.5kg
- The smallest dog weights 32kg - 45kg/2 = 9.5kg
(again, assuming a normal distribution).
If you want to learn more about means and ranges:
brainly.com/question/14532771
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Answer:
p > -0.2222
Step-by-step explanation:
7p + 3(-6p + 2) > 7p + 9 +1
7p + (3*-6p + 3*2) > 7p + 10
7p - 18p + 6 > 7p + 10
-11p - 7p > 10 - 6
-18p > 4
p > 4/-18
p > -0.2222
