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Leya [2.2K]
3 years ago
15

5^2x * 5^3 =5^9 what is x please help

Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0

Answer:

x = 3

Step-by-step explanation:

{5}^{2x}  \ast {5}^{3}  =  {5}^{9}  \\  {5}^{2x + 3}  =  {5}^{9}  \\ 2x + 3 = 9 \\ (bases \: are \: equal \: so \: exponents \: will \: also \: \\  be \: equal) \\ 2x = 9 - 3 \\ 2x = 6 \\ x =  \frac{6}{2}  \\  \huge \red { \boxed{x = 3}}

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Joe wrote an inequality
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Answer:Please see answer in explanation column

Step-by-step explanation:

A

The sum of a number and 7 is not more than 10

Given answer: x + 7 < 10  , This is false

Reason :Not more than 10 means at most 10, less than or equal to 10 , " or " not greater than 10 "and therefore the correct inequality  is written as

x + 7  ≤ 10

B

The product of a number and 4 is at least 20

Given answer: 4X > 20  ---- False

Reason :At least 20  means at no less than 20 " or " greater than or equal to 20  therefore the correct inequality  is written as

4X ≥ 20

C

The difference between a 15 and a number is at most 12

Given answer: 15-x>12----False

Reason :At most 12  means  " no more than 12 , "  " less than or equal to 12 , " or " not greater than 12"therefore the correct inequality  is written as

15-x  ≤  12

D

The quotient of a number and 8 is greater than or equal to

Given answer 8x <3 --False

Reason : It clearly stated greater than or equal to 3. Therefore the correct inequality is  8x  ≥ 3

6 0
2 years ago
Mario ran 24 miles in 3 hours. what was his average speed in miles per hour
kumpel [21]

Answer:

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Step-by-step explanation:

24/3 = 8

Check:

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8 0
3 years ago
Read 2 more answers
Solve each inequality. Then compare the solutions.<br><br> 3x +4&gt; 16<br> - 2x + 19&lt; 11
Makovka662 [10]

Answer:

3x + 4 > 16 \\ 3x > 16 - 4 \\  \frac{3x}{3}  >  \frac{12}{3}  \\ x > 4 \\  \\  - 2x + 19 < 11 \\  - 2x < 11 - 19 \\  - 2x <  - 8 \\  \frac{ - 2x}{ - 2}  >   \frac{ - 8}{   - 2}  \\ x > 4 \\  \\ comparing \\ 4 < x > 4

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3 years ago
The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of
Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

{\boxed{\sf Area=LB}}

  • Substitute the values

\hookrightarrow\sf x (6x-4)=20

\hookrightarrow\sf 6x^2-4x=20

\hookrightarrow\sf 6x^2-4x-20=0

  • Here a=6, b=-4, c=-20.
  • use quadratic formula

\hookrightarrow\sf x=\dfrac {1}{3}+\dfrac {1}{3}\sqrt {31} \quad or \quad \dfrac {1}{3}+\dfrac {-1}{3}\sqrt {31}

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3 years ago
I’m confused on this one
stellarik [79]

Its a. An enlargment on a scale of 3/1.

5 0
3 years ago
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