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Nikitich [7]
3 years ago
13

A local college offers scholarships to students who graduate in the top 1% of their high school classes according to GPA. If a h

igh school has 400 students graduating one year , how many students from that high school would be eligible for these scholarships.
Mathematics
1 answer:
tangare [24]3 years ago
4 0

Answer:

4 students would be eligible for the scholarships

Step-by-step explanation:

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Explain how you know 7/12 is greater than 1/3 but less than 2/3
Roman55 [17]
7/12
1/3=4/12
2/3=8/12

7/12>1/3
<span>7/12<2/3
</span>

convert all of these to a common denominator:
7/12 , 1/3 , 2/3
---
7/12 = 7/12
1/3 = 4/12
2/3 = 8/12
---
place into compound inequality:
---
(1/3=4/12) < (7/12=7/12) < (2/3=8/12)


3 0
3 years ago
Read 2 more answers
X+4 divided by x^2+16<br><br> Why can't it be simplified?
KonstantinChe [14]
Let's try to simplify x^2 + 16. It's a sum of two squares:

x^2 + 16 = 0

x^2 = -16

The problem is, we can't take a square root of a negative. This is where imaginary numbers come in.

Remember that square roots have a plus or minus symbol outside:

±√-16 = ±4i

Our two roots are 4i and -4i. Therefore, the trinomial simplifies to:

(x + 4i)(x - 4i)

If we attempt to divide x + 4 by these two binomials, we will find that 4 and 4i are not like terms. Therefore, we can't simplify this expression.
8 0
3 years ago
Name each polynomial by degree and number of terms of -7
denis-greek [22]

Answer: i couldn’t find the answer to this one either

Step-by-step explanation:

4 0
2 years ago
75,575 how do the values of the digit differ in the number?
Vsevolod [243]

Answer:

<u>7</u>5,575 - ten-thousands place; this 7 is worth 70,000

7<u>5</u>,575 - thousands place; this 5 is worth 5,000

75,<u>5</u>75 - hundreds place; this 5 is worth 500

75,5<u>7</u>5 - tens place; this 7 is worth 70

75,57<u>5</u> - ones place; this 5 is worth 5



8 0
3 years ago
X² + y² = 34<br>x + y =8​
Nataly [62]

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  = 34 \\ x + y = 8 \\ x = 8 - y \\ substitute \: x \: in \\  {x}^{2}  +  {y}^{2}  = 34 \\  {(8 - 4)}^{2}  +  {y}^{2}  = 34 \\  {(8 - 4) }^{2}  =  {y}^{2}  - 16y + 64 \\   {y}^{2}  - 16y + 64 +  {y}^{2}  = 34 \\  {2y}^{2}  - 16y + 64 = 34 \\ {2y}^{2}  - 16y + 64  - 34 = 0 \\  {2y}^{2}  - 16y + 30 = 0 \\ 2 {y}^{2}  - 6y - 10y + 30 = 0 \\ (2 {y}^{2}  - 6y) - (10y + 30) = 0 \\ 2y(y - 3) - 10(y - 3) = 0 \\ (2y - 10)(y - 3) \\ 2y = 10 \\ y  = \frac{10}{2}  \\ y = 5 \\ or \\ y = 3 \\ if \: y = 5 \:  \: x = 3 \\ if \: y = 3 \:  \:  x = 5

4 0
3 years ago
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