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Sedbober [7]
3 years ago
10

What is 0+0 if you have 0 friends and 0 cookies thank you have 0.1 cookies and friends?

Mathematics
2 answers:
scZoUnD [109]3 years ago
8 0

i got for my answer 0 at the total

solniwko [45]3 years ago
6 0

Answer: 0

Step-by-step explanation: if you have 0 friends and cookies then there would be 0 of anything in that question.

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Mark and Damien were in a hot dog contest. Mark ate 12 hot dogs. Damien ate 4/6 as many hot dogs as Mark. How many hot dogs did
mario62 [17]

Answer:

8

Step-by-step explanation:

4/6 of 12 is 8

7 0
3 years ago
Mason loves collecting sea glass from the beach. He recorded the weight of each jar full of sea glass. If he decided to distribu
lara31 [8.8K]

<em>The missing weights are:</em>

<em>2 2 2 1 11 12 12 2 24 22 24 3 37 22</em>

Answer:

Average = 12\frac{4}{7} \ lb

Step-by-step explanation:

Given

Weight of sea glass

To solve this question, we have to calculate the mean of the weight of the sea glass as follows;

Average = \frac{\sum x}{n}

Where n = number of sea glass

n = 14

So:

Average = \frac{\sum x}{n} becomes

Average = \frac{2 +2 + 2 + 1 + 11 +12 +12 +2 +24+22 +24 +3 +37+ 22}{14}

Average = \frac{176}{14}

Average = 12\frac{8}{14}

Simplify fraction

Average = 12\frac{4}{7}

<em>Hence; the weight of the sea glass would be </em>12\frac{4}{7}\ lb<em> </em><em>when evenly distributed...</em>

4 0
3 years ago
Given the equation,D=m/v if D=6/7 and =m+3 then m=.
mamaluj [8]

Answer:

m=18

Step-by-step explanation:

The equation given is D=\frac{m}{v}

and also we have that D=\frac{6}{7}, thus:

\frac{6}{7}=\frac{m}{v}

------------

I think the question is missing which variable is defined as =m+3, so I will solve for v=m+3 since is the only other variable in the equation.

substituting v=m+3  into \frac{6}{7}=\frac{m}{v}:

\frac{6}{7}=\frac{m}{m+3}

and we solve for m:

(m+3)(6)=7m\\6m+18=7m\\18=7m-6m\\18=m

m is equal to 18.

6 0
4 years ago
Which one of the following numbers are irrational ?
liq [111]

Answer: B and E are irrational numbers

5 0
3 years ago
If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)
svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

4 0
3 years ago
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