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Talja [164]
3 years ago
12

If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)

Mathematics
1 answer:
svp [43]3 years ago
4 0

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

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There are four main categories of transformations:

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A stiff transformation known as an isometry maintains perimeter and area while also preserving length and angle measurements. In other words, there is congruence between the preimage and the image. Translations, reflections, and rotations are therefore isometric, but dilations are not since the image and preimage are comparable, rather than congruent figures.

The transformation in the question will be isometric when the preimage of the rectangle before 360° rotation, will be congruent to the image after the rotation.

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The provided question is incomplete. For the complete question, refer to the attachment.

4 0
2 years ago
What will the length of segment I' J' be?<br>​
Ymorist [56]

Answer:

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To do this you multiply each coordinate by 8/3.

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H: (0,3) ---> (8/3*0, 8/3*3)

I: (1,1) ---> (8/3*1, 8/3*1)

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K: (2,5) ---> (8/3*2, 8/3*5)

Now we plot this. (Picture attached)

The new I' coordinate: (2.667, 2.667)

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The new length would be 8 - 2.667 so we can find the distance between the two points.

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8 - 2.667 equals 5.333

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