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kipiarov [429]
3 years ago
10

Factor: a^5+2a+a^4+2.

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0
(A+1) (a^4+2) that’s my answer
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Miguel an 2 of his friends share 7 rice cakes equally.
svlad2 [7]
7 ÷ 2 = 3.5 or 3 and 1/2
3 0
3 years ago
Read 2 more answers
A 99% confidence interval for the sugar content (per 5 oz. serving) of a shipment of strawberries is 5.9 to 8.3 grams.
gavmur [86]

Answer:

Sample mean = 7.1

Margin of error = 0.465

Step-by-step explanation:

Formula for confidence interval is;

CI = x¯ ± zE

Where;

x¯ is sample mean

z is critical value at confidence level

E is margin of error.

z for 99% Cl is 2.58

We are told the CI is 5.9 to 8.3.

Thus;

5.9 = x¯ - 2.58E - - - - (1)

8.3 = x¯ + 2.58E - - - - (2)

Add both equations together to get;

14.2 = 2x¯

x¯ = 14.2/2

x¯ = 7.1

Put 7.1 for x¯ in eq 1 to get;

5.9 = 7.1 - 2.58E

7.1 - 5.9 = 2.58E

E = 1.2/2.58

E = 0.465

5 0
3 years ago
F(x) = 3x2 + 6x – 18<br> Find f(10)
ozzi

Answer:

=

(

x

2

+

6

)

(

x

+

3

)

Step-by-step explanation:

[Grouping the first 2 terms together and the 2md 2 terms together.]

x

3

+

3

x

2

+

6

x

+

18

=

(

x

3

+

3

x

2

)

+

(

6

x

+

18

)

[Common factor]

=

x

2

(

x

+

3

)

+

6

(

x

+

3

)

{Taking the common bracket]

=

(

x

2

+

6

)

(

x

+

3

)

~Hope this helps! :)

5 0
3 years ago
Read 2 more answers
Pls help i will give brainliest
pentagon [3]

I'm Sorry I not good when it comes to tax but it might be around 21.30 maybe I most likely am wrong

3 0
2 years ago
Read 2 more answers
An electronics company packages its product in cube-shaped boxes. These boxes are placed into a larger box that measures 3 ft lo
gladu [14]

The number of boxes fitted in the larger container is found out by the volume of both boxes.

The number of boxes fitted into the larger container is 480.

<h3>What is the volume?</h3>

The volume can be defined as the space occupied by an object in three dimensions.

Given that the edge of the cube box is 1/4 ft. The dimensions of the larger box are 3 ft long, 1 1/4 ft wide, and 2 ft.

The volume of the cube box is calculated as given below.

V_s = s^3

Where Vs is the volume of the cube box and s is the edge of the cube box.

V_s = \dfrac {1}{4}^3

V_s = 0.015625\;\rm ft^3

The volume of the larger box is calculated as given below.

<em />V = l \times w\times h

Where V is the volume, l is length, w is width and h is the height of the larger box.

V = 3 \times \dfrac {5}{4} \times 2

V = 7.5\;\rm ft^3

The number of cube boxes fitted into the larger box is calculated as given below.

No. \; of \;boxes = \dfrac {V}{V_s}

No. \; of \;boxes = \dfrac {7.5}{0.015625}

No. \; of \;boxes = 480

Hence we can conclude the number of boxes fitted into the larger container is 480.

To know more about the volume, follow the link given below.

brainly.com/question/1578538.

8 0
2 years ago
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