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seropon [69]
3 years ago
14

A radar gun measured the speed of a baseball at 103 miles per hour. If the baseball was actually going 102.8 miles per hour, wha

t was the percent error in this measurement?
Mathematics
2 answers:
zimovet [89]3 years ago
5 0

Answer:

.998%

Step-by-step explanation:

102.8/103 = .9980582524

IgorC [24]3 years ago
5 0

Answer:

The percent error in this measurement is 0.194%.

Step-by-step explanation:

Given : A radar gun measured the speed of a baseball at 103 miles per hour. If the baseball was actually going 102.8 miles per hour.

To find : What was the percent error in this measurement?

Solution :

The actual speed is 103 miles per hour.

The estimated speed is 102.8 miles per hour.

The percentage is given by,

\text{Percentage}=\frac{\text{Actual-Estimated}}{\text{Actual}}\times 100

\text{Percentage}=\frac{103-102.8}{102.8}\times 100

\text{Percentage}=\frac{0.2}{102.8}\times 100

\text{Percentage}=0.194\%

Therefore, the percent error in this measurement is 0.194%.

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