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Rainbow [258]
3 years ago
12

researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 40% 40 % of this population prefer

s the color red. If 14 14 buyers are randomly selected, what is the probability that exactly 2 2 buyers would prefer red? Round your answer to four decimal places.
Mathematics
1 answer:
TEA [102]3 years ago
7 0

Answer: the probability that exactly 2 buyers would prefer red is 0.0320

Step-by-step explanation:

We would assume a binomial distribution for the color preferences of new car buyers. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - r) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 40% = 40/100 = 0.4

q = 1 - p = 1 - 0.4

q = 0.6

n = 14

x = r = 2

Therefore,

P(x = 2) = 14C2 × 0.4^2 × 0.6^(14 - 2)

P(x = 2) = 91 × 0.16 × 0.0022

P(x = 2) = 0.0320

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Answer: the speed of the plane in still air is 135 miles per hour

the speed of the wind is 15 miles per hour

Step-by-step explanation:

Let x represent the speed of the plane in still air

Let y represent the speed of the wind.

The distance travelled by the plane is 600 miles.

Distance travelled = speed × time

It takes the plane 5 hours against the wind. This means that the total speed is (x-y) miles per hour. Therefore,

600 = 5(x- y) = 5x - 5y - - - - - - - 1

It takes the plane 4 hours with the wind. This means that the total speed is (x+y) miles per hour. Therefore,

600 = 4(x+ y) = 4x + 4y - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 5, it becomes

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Adding both equations

5400 = 40x

x = 5400/40 = 135

Substituting x = 135 into equation 1, it becomes

4 × 135 + 4y = 600

540 + 4y = 600

4y = 600 - 540 = 60

y = 60/4 = 15

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A 12-inch long board is basically a feet long

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<h3><u><em>Please mark this as brainliest</em></u></h3><h3><u><em>hope this helps</em></u></h3><h3><u><em>Thank you</em></u></h3><h3><u><em>: )</em></u></h3>
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