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MaRussiya [10]
3 years ago
10

What IS 20 divided by 13 ?

Mathematics
2 answers:
diamong [38]3 years ago
8 0

<em>20/13</em>

<em>and as you know it can only go into 20 once. </em>

<em>so you can do this 13/13 and 20/13</em>

<em>that leaves 7 of 20 and 13</em>

<em>wait if this is confusing then,</em>

<em>_______________________________________________</em>

<u><em>20/13 - 13/13 = 7/1</em></u>

<em>_______________________________________________</em>

<em>= 1.53</em>

goldenfox [79]3 years ago
4 0

Solution,\mathrm{Convert\:improper\:fractions\:to\:mixed\:numbers}:\quad \frac{20}{13}=1\frac{7}{13}

Steps:

\frac{20}{13}

\mathrm{Long\:Division}\:\frac{20}{13}:\quad 1\quad \mathrm{Remainder}\quad \:7

Convert\:to\:mixed\:number:\:Quotient\frac{Remainder}{Divisor},\\\frac{20}{13}=1\frac{7}{13}

Hope\: This\: Helps!!!

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Liono4ka [1.6K]
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3 years ago
Can someone help me w questions 1 and 2 i’ll give u brainliest
Leni [432]

Answer:

1. x^2+5

2.x^2-6x+9

Step-by-step explanation:

these are just translations up and to the right.

since the f(x)=x^2

the transformations would be

1. g(x)=x^2+5

2.g(x)=(x-3)^2 = x^2-6x+9

4 0
2 years ago
Find limit as x approaches 1 for x-1/ x^2-3x+2
zysi [14]

I'm going to assume that you meant the following:

  (x-1)

---------------

x^2-3x+2


Factoring the denominator, we get:

  (x-1)

------------  

(x-1)(x-2)

Notice that we have x-1 in both the numerator and the denominator.  This factor cancels.  HOWEVER:  x can still not equal 1, which would lead to div. by zero.  With the factor x-1 cancelled, we have   1 / (x-2).  As x approaches 1 from either side, y approaches 1 / (1-2), or 1 / (-1), or -1.  Thus, the limit exists and is -1.

8 0
3 years ago
Which expression is equivalent to n2 + 26n + 88 for all values of n?
Lelechka [254]

Answer:

Option B is correct.

The expression which is equivalent to  n^2+26n+88  is; (n+22)(n+4)

Explanation:

Given the equation: n^2+26n+88 for all values of n.

The quadratic equation in this form; ax^2+bx+c =0

First find two numbers that multiply to give ac and add to give b.

From the given equation;

a =1 , b = 26 and c =88

then,

the two number that multiply to give ac =88 is, 22 or 4

and they add up to give b=26 (i.e 22+4)

Now, rewrite the middle term i.e 26n with 22n and 4n , we have

n^2+22n+4n+88=0

Now, factor the first two terms and last two terms,

n(n+22)+4(n+22)

we see that (n+22) is common to both terms so, we have;

(n+22)(n+4)

Therefore, the expression (n+22)(n+4) is equivalent to  n^2+26n+88

Check:

(n+4)(n+22) = n\cdot n+ 22n+4n+88=n^2+26n+88   [ True]



5 0
3 years ago
Read 2 more answers
Is this a reflection
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Answer:

yes

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it is reflected across the y axis

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