Answer: 484
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Work Shown:
First let's compute f(2). We replace every x with 2 and then use PEMDAS to simplify
f(x) = -x^4 + 5x - 4x^2
f(2) = -(2)^4 + 5(2) - 4(2)^2
f(2) = -16 + 5(2) - 4(4)
f(2) = -16 + 10 - 16
f(2) = -6 - 16
f(2) = -22
Then we square this result to find the value of ![[ f(2) ]^2](https://tex.z-dn.net/?f=%5B%20f%282%29%20%5D%5E2)
![f(2) = -22\\\\\left[ f(2) \right]^2 = [ -22 ]^2\\\\\left[ f(2) \right]^2 = 484](https://tex.z-dn.net/?f=f%282%29%20%3D%20-22%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20%5B%20-22%20%5D%5E2%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20484)
The equation for a line that passes through the point of (3, 9) and has a slope of 2 in slope intercept form is y=2x+3
<span>You did not include the equations that you want to assess whether they can be used to solve for the radius (r).
Likely, the equation of the circumference, C = 2*Pi*r is included, if so => r = C / (2*Pi).
If you round Pi to 3.14, the equation may be written r = C / 6.28.</span>
Answer:
7−2x
Step-by-step explanation:
1 Collect like terms.
(4+3)+(-7x+5x)
(4+3)+(−7x+5x)
2 Simplify.
7-2x
7−2x
