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inn [45]
1 year ago
13

Given:B is the midpoint of AC. Complete the statement. If AB = 7,then BC = _____, and AC = ____.

Mathematics
1 answer:
Alex73 [517]1 year ago
5 0

Midpoint

We know AC is a segment and B is its midpoint. This means the length of the segment AB is half the length of the segment AC. This also means the length of the segment BC is half the length of AC, and equal to AB.

This can be visualized as follows:

Since AB=7, then BC = 7 and AC=AB+BC = 14

Answer: BC = 7, and AC=!4

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Which is the best prove why.5 gallon bucket of paint for $97.45 of a 1 gallon bucket of paint for 21.95.?
Greeley [361]
97.45 / 5 = 19.49 per gallon

and then there is 21.95 per gallon

the better deal would be the 5 gallon bucket for 97.45 because if u buy it this way, it is cheaper by the gallon
4 0
3 years ago
he measurements of two sides of a triangle are 4 cm and 20 cm. What could be a measurement of the third side of the triangle?
hodyreva [135]

Answer:

80

Step-by-step explanation:

every triangle adds up to 180 sort of, in this case, turn 4 into 40. 40+20=60 so add 80 to be 180!!!

4 0
2 years ago
I need help with 2. 3. 8 and 13 please help me
Crank

Answer:

all work is shown and pictured

6 0
3 years ago
Mindy and Troy combined ate 9 99 pieces of the wedding cake. Mindy ate 3 33 pieces of cake and Troy had 1 4 4 1 ​ start fraction
saul85 [17]

Answer:

(a)There are 24 cakes in total

(b)There are 15 pieces of cakes left

Step-by-step explanation:

Let the total cakes=x

Let number of cakes eaten by Mindy=m

Let number of cakes eaten by Troy=t

Now:

m=3

Since m+t=9

3+t=9

t=9-3=6

The Number of Pieces of Cake Left in Total=x-(t+m)

Since Troy had \frac{1}{4} of the total cake

\frac{1}{4} of x=6

\frac{1}{4} X x=6

x=6X4=24

(a)There are 24 cakes in total

(b)The Number of Pieces of Cake Left in Total=x-(t+m)=24-9=15 cakes

5 0
3 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


Firstly, solve inside the parentheses: \sqrt{(2)^2+(-5)^2}


Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



ZX:

\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

8 0
3 years ago
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