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Pavlova-9 [17]
4 years ago
13

Plz help me me I will mark brainlest for correct answer with explanation​

Mathematics
1 answer:
Karo-lina-s [1.5K]4 years ago
7 0

Answer:

3,4

Step-by-step explanation:

r=b

Which is coded

to 3=4

Now you change to = to ,

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20

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19.55 can be either 19 and 20, but it is closer to 20!

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The probability that Evan purchases a comic book from the bookstore (event A) is 0.67, and the probability that Glen purchases a
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Evaluate y = 3x, when x = 5<br><br> y = 243<br> y = 125<br> y = 15
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Step-by-step explanation:

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Question 12
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Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4
Vladimir79 [104]

Answer:

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3) ⇒ 2nd

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is 32y^{10}-24

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ 32y^{10}-24 = 8(  y^{10}-3)  ⇒ the same with the answer

∴ The expression 32y^{10}-24 = 8(y^{10}-3) is completely factored

∵ The expression is 20y^{7}+10y^{2}

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of y^{7} and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ 20y^{7}+10y^{2}=10y^{2}(2y^{5}+1) ⇒ not the same with the answer

∵ The expression is 16y^{5}+12y^{3}

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of y^{5} and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) ⇒ the same with the answer

∴ The expression 16y^{5}+12y^{3}=4y^{3}(4y^{2}+3) is completely factored

The expressions that completely factored are:

32y^{10}-24 = 8(y^{10}-3)

16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)

3 0
3 years ago
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