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torisob [31]
3 years ago
13

Lee walked a total of 4.48 miles. he walks 1.4 miles each hour. how long did lee walk?​

Mathematics
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

3.2 hrs

Step-by-step explanation:

Recall that distance = rate times time, so:

4.48 mi = (1.4 mph)(time), and:

                                          4.48 mi

the elapsed time was ------------------- = 3.2 hours

                                       1.4 mph

laila [671]3 years ago
4 0

Answer - 3.2 hours

because 4.48 miles divided by 1.4 mph equals 3.2

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Ivahew [28]

Answer:

The first is  \frac{4}{10}

The second is \frac{10}{16}

The third is \frac{3}{10}

The fourth is \frac{6}{21}

The fifth is \frac{3}{5}

5 0
2 years ago
Idk how to do this someone help me
Vlad [161]
I'm thinking its 4 to the 12 power but I am not completely sure on this
4 0
3 years ago
Read 2 more answers
Help help please.....Thanks
Novosadov [1.4K]

Hey there! :)

Answer:

56.7 kg.

Step-by-step explanation:

Use the density formula to solve for the mass:

D = m/V.

Rearrange in terms of mass, or 'm':

DV = m.

Solve for the volume:

0.06 × 0.9 × 1.5 = 0.081 m³.

Plug this into the equation along with the density:

700 × 0.081 = 56.7 kg.

5 0
3 years ago
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
James estimate the product of 48 and 53 is that reasonable
Debora [2.8K]
50 x 50= 2500.............
8 0
3 years ago
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