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Mnenie [13.5K]
3 years ago
8

Presently we can solve problem instances of size 30 in 1 minute using algorithm A, which is a algorithm. On the other hand, we w

ill soon have to solve probleminstances twice this large in 1 minute. Do you think it would help to buy a faster( and more expensive) computer?
Computers and Technology
1 answer:
Brums [2.3K]3 years ago
3 0

Answer:

No, if the algorithm is properly written to solve problems with minimal resources like RAM and processor speed.

Explanation:

Rather than buy a faster or more expensive computer simply upgrade the RAM else you may have to buy new computer each the size of problem instances increases.

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What do you call a firewall that is connected to the internet, the internal network, and the dmz?
Firlakuza [10]
<span>Three-pronged firewall hope this helps!</span>
3 0
3 years ago
2) What is the value stored in the variable z by the statements below?
Dmitriy789 [7]

Answer:

7

Explanation:

Because the q.length is a inbuilt function in the programming which used to get the length of the array. In the array, there are 7 values are store. Therefore, the size 7 store in the variable z.

For example:

int[] array={1,2};

int x = array.length;

the answer of above code is 2, because the elements present in the array is 2.

 

5 0
3 years ago
From a neural network with 11 input variables, one hidden layer with three hidden units, and one output variable, how many param
e-lub [12.9K]

Answer:

40

Explanation:

Given that:

A neural network with 11 input variables possess;

one hidden layer with three hidden units; &

one output variable

For every input, a variable must go to every node.

Thus, we can calculate the weights of weight with respect to connections to input and hidden layer by using the formula:

= ( inputs + bias) × numbers of nodes

= (11 + 1 ) × 3

= 12 × 3

= 36 weights

Also, For one hidden layer (with 3 nodes) and one output

The entry result for every hidden node will go directly to the output

These results will have weights associated with them before computed in the output node.

Thus; using the formula

= (numbers of nodes + bais) output, we get;

= ( 3+ 1 ) × 1

= 4 weights

weights with respect to input and hidden layer total = 36

weights with respect to hidden and output layer total = 4

Finally, the sum of both weights is = 36 + 4

= 40

6 0
2 years ago
Rutherford presented his first slide, which consisted of a conceptual map of
sergejj [24]

Your answer would be D.

8 0
3 years ago
Read 2 more answers
What is the worst case running time of a linear search?
shtirl [24]

Answer:

The worst case running time of a linear search is O(N).

Explanation:

In a linear search, you will run the program looking at each array position until you find your desired information.

The best case scenario is when you find it at the first position.

The worst case scenario is when you find the value at the last array position. So, in a N-length array, the information is at position N. This means that the worst case running time of a linear search is O(N).

3 0
3 years ago
Read 2 more answers
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