120^ is the answer for this problem
12 | 12
— — —
20 | 6
ab = 2 * 6 = 12
4b/2 = (4 * 6) / 2 = 24 / 2 = 12
a^3 + 2b = 2^3 + 2 * 6 = 8 + 2 * 6 = 8 + 12 = 20
b^2 / (4 + a) = 6^2 / (4 + 2) = 6^2 / 6 = 36 / 6 = 6
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Recall that the area under a probability curve is always 1.0. Here we have a probability distribution from 10.6 to 18.6 minutes, of length 10 minutes, so the height of the probability "curve" is 1.0 / 10, or 0.1.
To answer this question, find the area under the probability "curve" between 13.8 and 16.8 minutes. The difference between 13.8 and 16.8 is 3 units, so the desired probability is 3(0.1), or 0.30.
This question can be answered by graphing, but first you need to write an equation using slope- intercept form
y=mx+b , where m is the slope and b is the y intercept
