The ages and grades of some of the 18 girls on a club soccer team are shown in the table.

Hanson and his classmates placed colored blocks on a scale during a science lab. The blue block weighed 8.1 pounds and the green

Alexeev081 [22]

Answer:

4.342

Step-by-step explanation:

8.1 - 3.758 = 4.342

When you are trying to find the amount of difference between two values you subtract the value less than the other and there you go, the solution!

I hope it was as simple as that and that this helped!

3 0

2 years ago

What is the volume of the rectangular prism - i ready. 1/3 ft some of. The answers 1 1/9 feet3- 10 ft3 - 2/9 ft3 - 3 1/3 ft3

Kamila [148]

Answer:

$3\frac{1}{3}\ ft^3$

Step-by-step explanation:

A rectangular prism is a polyhedron with six rectangular faces. The volume of a prism is given by:

Volume = width * height * length

From the diagram, the rectangular prism is made up of cubes. Each cube is has a size of 1/3 ft by 1/3 ft.

The height of the prism is made up of 5 cubes. Height = 5 * 1/3 = 5/3 ft.

The length of the prism is made up of 3 cubes. length = 3 * 1/3 = 1 ft.

The width of the prism is made up of 2 cubes. Width = 2 * 1/3 = 2/3 ft.

The volume of the prism = width * height * length = 2/3 * 5/3 * 1 = 10/9 ft³ = $3\frac{1}{3}\ ft^3$

6 0

3 years ago

Read 2 more answers

A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.

melisa1 [442]

Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

$\overline{OB}:\overline{AB} = 1:2$
$\overline {OB}:10 = 1:2$
$\overline{OB} = \frac{1}{2}(10) = 5$

Similarly, we have

$\overline{AO}:\overline{AB} = \sqrt{3}:2$
$\overline {AO}:10 = \sqrt{3}:2$
$\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}$

Now, to find the lengths of the diagonals,

$\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}$
$\overline{BC} = 2(\overline{OB}) = 10$

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0

3 years ago

Having trouble with subtracting and regrouping mixed numbers. 5 1/8 -2 4/8.

Mkey [24]

You will need to convert them into improper fractions, subtract them, and convert them back to mixed numbers.
5 1/8 - 2 4/8
41/8 - 20/8
21/8
2 5/8
Your answer is 2 5/8.

5 0

3 years ago

Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8

Dima020 [189]

Let $f(x,y,z)=x+y+z-8e^{xyz}$ . The tangent plane to the surface at (0, 0, 8) is

$\nabla f(0,0,8)\cdot(x,y,z-8)=0$

The gradient is

$\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)$

so the tangent plane's equation is

$(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8$

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by $t$ , then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

$(1,1,1)t+(0,0,8)=(t,t,t+8)$

or $x(t)=t$ , $y(t)=t$ , and $z(t)=t+8$ .

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0

3 years ago