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3 years ago

Question 1-4

Mathematics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

step 2 to step 3

Step-by-step explanation:

step 2

2x - 7 = 3 ( add 7 to both sides )

2x = 10 ( error was made here in that they had - 4 )

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Help me please help me help please

Anestetic [448]

Answer:

Step-by-step explanation:

-4/-1 = 4

6 0

2 years ago

What is the simplified form of 5 square root x • 5 square root x • 5 square root x • 5 square root x?

Lina20 [59]

Answer:

Step-by-step explanation:

The expression $\sqrt[5]{x} *\sqrt[5]{x}* \sqrt[5]{x} *\sqrt[5]{x}$ simplifies to $\sqrt[5]{x*x*x*x} = \sqrt[5]{x^4}$

A radical can be written as a fractional exponent. The index of a radical is the denominator of its fractional exponent.

$x^\frac{4}{5}$

5 0

4 years ago

Please help!!!!!!!!!!!!!!!

Lina20 [59]

7040 yards in 4 miles

3 0

3 years ago

Could someone please help me:) I am stick and I am not sure what to do

Delicious77 [7]

Answer:

Part 5.1.1:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

We are given that:

$\displaystyle \sin 2A = \frac{\sqrt{15}}{8}$

Part 5.1.1

Recall that:

$\displaystyle \sin^2 \theta + \cos^2 \theta = 1$

Let θ = 2A. Hence:

$\displaystyle \sin ^2 2A + \cos ^2 2A = 1$

Square the original equation:

$\displaystyle \sin^2 2A = \frac{15}{64}$

Hence:

$\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1$

Subtract:

$\displaystyle \cos ^2 2A = \frac{49}{64}$

Take the square root of both sides:

$\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}$

Since 0° ≤ 2A ≤ 90°, cos(2A) must be positive. Hence:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2

Recall that:

$\displaystyle \begin{aligned} \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &= 1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}$

We can use the third form. Substitute:

$\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1$

Solve for cosine:

$\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}$

In conclusion:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

(Note that since 0° ≤ 2A ≤ 90°, 0° ≤ A ≤ 45°. Hence, cos(A) must be positive.)

4 0

3 years ago

Math definitely isn't my greatest subject, if anyone knows how to do this and can explain it to me please help!

Law Incorporation [45]

Answer:

y-1 = 5/3(x-3)

Choice C

Step-by-step explanation:

slope = (y2-y1)/(x2-x1)

(3,1) (6,6)

m = (6-1)/(6-3)

m = (5/3)

the point slope form of a line is given by

y-y1 = m(x-x1)

You have point (3,1)

y-1 = 5/3(x-3)

Choice C

8 0

3 years ago