3 years ago

Question 1-4

Mathematics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

step 2 to step 3

Step-by-step explanation:

step 2

2x - 7 = 3 ( add 7 to both sides )

2x = 10 ( error was made here in that they had - 4 )

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3 years ago

Given that a = 2,5= 2 and C = -1 work out 2b – 3ac

poizon [28]

Step-by-step explanation:

2b-3ac

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= 4+6

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3 years ago

What’s the correct answer for this question?

g100num [7]

Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f

tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

= 180° - (45° + 120°)

= 180° - 165°

= 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

$\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}$

$\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

$\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

PR = $\frac{12\text{sin}(120)}{\text{sin}(15)}$

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0

3 years ago