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quester [9]
3 years ago
15

Help me please asappp!!!!​

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0

Answer:

For the function y=2x^2:

y=0\\y=2\\y=8

For the second function y=2^x:

 y=1\\y=2\\y=4

Step-by-step explanation:

You only need to make the following substitution:

For the first function y=2x^2:

When x=0

y=2x^2\\ y=2(0)^2\\ y=0

When x=1

y=2(1)^2\\ y=2(1)^2\\ y=2

When x=2

y=2x^2\\ y=2(2)^2\\ y=2*4\\ y=8

For the second function y=2^x:

When x=0

y=2^x\\ y=2^0\\ y=1

When x=1

y=2^x\\ y=2^1\\ y=2

When x=2

y=2^x\\y=2^2\\ y=2^2\\ y=4

djverab [1.8K]3 years ago
5 0

ANSWER

When x=1, y =2{x}^{2} is 2

and y =  {2}^{x} is 2

When x=2, y =2{x}^{2} is 8

and y =  {2}^{x} is 4

EXPLANATION

The given functions are:

y =2{x}^{2}

and

y =  {2}^{x}

We want to find the functional values for the given x-values.

When x=1,

y = 2( {1})^{2}  = 2

and

y =  {2}^{1}  = 2

When x=2,

The first function gives us:

y = 2 {(2)}^{2}  = 8

and the second function gives

y =  {2}^{2}  = 4

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