Can anyone help need help!! :(

Garrett and Carter went to the movies last weekend. Together they bought 2 drinks and 2 popcorns. They spent a total of $12.50.

Tatiana [17]

Since Garrett and Carter bought popcorn and drinks, we have to figure out how much money is 1 drink and 1 popcorn. I figured the best way is to figure out half of $12.50 because 2 drinks and 2 popcorn cost that amount of money. You divide $12.50 by 2 to figure out half of that amount. The quotient equals to $6.25.

4 0

4 years ago

What’s the area of this figure?

11Alexandr11 [23.1K]

Answer:

13 sq cm.

Step-by-step explanation:

To find the area of this irregular figure, we will need to find the areas of a rectangle and triangle within this figure.

To find the area of the rectangle, we can simply do:

1 × 4= 4 sq cm.

Now, this is where it gets a little trickier. To find the area of the triangle, we will first need to determine the base and height.

We can see from the diagram that to find the base, we need to subtract:

7-4= 3 cm. This is the base of ONLY the triangle.

To find the height, we will need to do:

5+1= 6 cm. This is the total height of the entirety of the triangle.

We can now use the Triangle Area formula: $\frac{1}{2}$ (bh), to calculate the area of the triangle.

$\frac{1}{2}$ (6*3)= 9 sq cm.

Finally, add the areas of the rectangle and triangle together, giving you:

9+4= 13 sq cm.

3 0

4 years ago

Please answer this question 7/10k=21 I will give you brainliest.

vredina [299]

Answer:

30

Step-by-step explanation:

10×7/10=21×10

7÷7=210÷7

answer=30

6 0

3 years ago

Read 2 more answers

4) Kevin and his team do not know what direction Mike went when he left the trail. This means that they will have

aalyn [17]

Answer:

Step-by-step explanation:

Distance traveled by Mike in 12 hours = 4 * 12 = 48 km

This will become the radius of the circle

r = 48 km

Area of the circle to be searched = πr²

= 3.14 * 48 * 48

= 7234.56 square km

8 0

4 years ago

Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable

bekas [8.4K]

Answer:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

$u=\frac{y}{x}$

Multiply both sides by x:

$ux=y$

Second step: Differentiate the substitution:

$u'x+u=y'$

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

$u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}$

$u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}$

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of $x^2$ so I'm going to divide top and bottom by $x^2$ :

$u'x+u=\frac{u+u^2}{3+u^2}$

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

$u'x=\frac{u+u^2}{3+u^2}-u$

Find a common denominator: Multiply second term on right hand side by $\frac{3+u^2}{3+u^2}$ :

$u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}$

Combine fractions while also distributing u to terms in ( ):

$u'x=\frac{u+u^2-3u-u^3}{3+u^2}$

$u'x=\frac{-u^3+u^2-2u}{3+u^2}$

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

$u' \frac{3+u^2}{-u^3+u^2-2u}x=1$

Divide both sides by x:

$\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}$

Reorder the top a little of left hand side using the commutative property for addition:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0

3 years ago