Answer:
Step-by-step explanation:
Consider curl
where
is a scalar function and F is a vector function

i j k



Answer:
O is in between m and p so it is 6
Step-by-step explanation:
In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.
Scot would have 4 football cards..
Not 100% sure
Sorry =,(
Answer:
Step-by-step explanation:
solve each inequality:
A : x+6<8 , x<-8-6 , x<-14
B: x+4≥-6 , x≥-10
C: x-3>-10 , x>-7
D:x≤-9
since -12 is on the left side of the number line then x≤ -9 would be the solution