The only way I can see to work this out is long hand writing out all prime numbers multiply them by 2 and looking for prime number interferes therefore = 3+7=10
We have an arithmetic progression:
An arithmetic progression is a sequence of numbers such that the diference between the consecutive terms is constant.
Explicit formula:
an=a₁+(n-1)*d
a₁ is the first term
d is de common diference
n is the numbers of terms
In this case:
a₁=-9
d=an-an-1=a₂-a₁=-16-(-9)=-16+9=-7
an=-9+(n-1)*(-7)
an=-9-7n+7
an=-7n+-2
a₁=-7*1-2=-9
a₂=-7*2-2=-14-2=-16
a₃=-7*3-2=-21-2=-23
a₄=-7*4-2=-28-2=-30
a₅=-7*5-2=-35-2=-37
a₆=-7*6-2=-42-2=-44
Answer:
x=4
Step-by-step explanation:
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Answer:
equation A
Step-by-step explanation:
Lets find how many boys there are.
First we add the ratios:
7 + 5 = 12
Then we divide the total number of students by this:
240 / 12 = 20
Now to find out how many boys there are, we times this by the ratio of boys:
20 x 5 = 100
Finally we divide the number boys, by the total number of students. We then times this number 100 to change it from a decimal to a percentage.
100 / 240 = 0.41666 (Multiply this by 100 to get the percentage)
0.41666 x 100 = 41.67%