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FromTheMoon [43]
2 years ago
12

Twice a certain number is 58. 4 times that number will be a) 4x58 b) 58 + 4 c) 58x2 d)8x58

Mathematics
1 answer:
irga5000 [103]2 years ago
4 0

Answer:

c) 58x2

Step-by-step explanation:

Twice the number 29 is 58

So, 29 is related to 58

Therefore 29*4 = 58*2

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What is the nth term of 4 1 -2 -5 -8
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The nth Term of this number is -3n+7

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There is a 5% sales tax on clothing at your favorite store you've gone shopping 4 times how much tax did you pay each time ?
salantis [7]
All you have to do is the amount she bought divided by 0.05 and then add the answer you get to the amount she bought each time
8 0
3 years ago
The table shows the relationship
Airida [17]

The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0

  • Change in weight per day of hibernation = - 0.03
  • Change in weight for 115 days = - 3.45 ounces

A linear model can be created using the data in the table given using a regression calculator or excel ;

The linear model obtained in the form y = m + bx is :

  • y = - 0.03x + 0
  • y = change in weight
  • x = number of days of hibernation
  • Intercept = 0
  • Slope = -0.03

  • The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.

  • Using the regression equation, substitute, the vlaue of x = 115
  • -0.03(115) + 0 = - 3.45

Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.

Learn more :brainly.com/question/18405415

8 0
2 years ago
A company’s profit in dollars is modeled by the equation p(x) = –0.5x2 + 100x, where x represents the number of units sold.
serg [7]

Answers:

a. The company needs to sell 100 units to reach the maxmum profit.

b. The company's maximum profit is $5,000.

Solution:

a. How many unit does the company need to sell to reach the maximum profit?

p(x)=-0.5x^2+100x

This is a quadratic equation, and its graph is a parabola vertical (because the veriable "x" is square). Comparing with the general form:

p(x)=ax^2+bx+c; a=-0.5, b=100, c=0

a=-0.5<0 (negative), then the parabola opens downward, and it has a maximimun value (maximum profit) at its vertex.

We can find the abscissa of the vertex (units that the company needs to sell to reach the maximum profit using the following formula:

x=-b/(2a)

Replacing b by 100 and a by -0.5 in the formula above:

x=-100/[2(-0.5)]

x=-100/(-1)

x=100

The company needs to sell 100 units to reach the maximum profit.


b. What's the company's maximum profit?  

To determine the maximum profit we substitute the value of "x" obrained in part "a" in the quadratic equation:

x=100→p(100)=-0.5(100)^2+100(100)

p(100)=-0.5(10,000)+10,000

p(100)=-5,000+10,000

p(100)=5,000

The company's maximum profit is $5,000.

6 0
3 years ago
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