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just olya [345]
4 years ago
14

A polynomial is factorable, but it is not a perfect square trinomial or a

Mathematics
2 answers:
Talja [164]4 years ago
7 0

Answer:

So in this problem, we're told that a polynomial is fact herbal and it's not a perfect square. Try no meal or a difference of two squares. Can you factor the pie? Nomi bite or polynomial without finding the G C F. So no Jacey after is allowed. So if it's not a perfect squared, try no meal. So not a perfect square. We know it's not this, and we also know it's not a difference of two squirt if it's not any of these or if it's not either of these, but we can't find the G. C F. There are three different ways we could find the factored form. You could do it by grouping where you separating the polynomial into two parts and factor them individually before combining. You could also use the sum or a difference of cubes. This is for a cubic or a um, polynomial of third degree, and you could also use fractional or negative exponents. So even if you can't find the G c f or use these methods, there are still three ways you can factor the

Step-by-step explanation:

Glad i could help!

Scilla [17]4 years ago
6 0

Answer:

So in this problem, we're told that a polynomial is fact herbal and it's not a perfect square. Try no meal or a difference of two squares. Can you factor the pie? Nomi bite or polynomial without finding the G C F. So no Jacey after is allowed. So if it's not a perfect squared, try no meal. So not a perfect square. We know it's not this, and we also know it's not a difference of two squirt if it's not any of these or if it's not either of these, but we can't find the G. C F. There are three different ways we could find the factored form. You could do it by grouping where you separating the polynomial into two parts and factor them individually before combining. You could also use the sum or a difference of cubes. This is for a cubic or a um, polynomial of third degree, and you could also use fractional or negative exponents. So even if you can't find the G c f or use these methods, there are still three ways you can factor the.

Step-by-step explanation:

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Which inequality has a dashed boundary line when graphed? A y>=3/5x+1 B y>= -1/3x+1 C y>3x+1
Ket [755]

Answer: C y>3x+1

Step-by-step explanation:

  • When we graph an  inequality with strictly greater of less than sign ('<' or '>'), then the graph has a dashed boundary line .
  • Further it indicates that it does not include the points on the line.

From all the given options , only C contains inequality with '>' sign .

Hence, y>3x+1 is the inequality has a dashed boundary line when graphed.

hence, the correct option is C.

4 0
3 years ago
There are 12 basketball players on the team. In order to complete the main composition of the team for the
lesantik [10]

Step-by-step explanation:

We have been given that a basketball team has 12 players and the coach wants to pick which 5 players will start today's game.

We will use combinations formula to solve our given problem. , where,

n = Number of total items,

r = Number of items being chosen at a time.

Upon substituting our given values in combinations formula we will get,

Therefore, the coach can choose from 792 combinations

4 0
3 years ago
Plz help with this question 10 points plz
Elodia [21]

9514 1404 393

Answer:

  (d)  x = 14√3; y = 14

Step-by-step explanation:

The side length ratios in a 30°-60°-90° triangle are 1 : √3 : 2. That is, the short side (y) is half the length of the hypotenuse (28). Only one answer choice matches ...

  y = 28/2 = 14

  x = y√3 = 14√3

_____

It is a good idea to remember these ratios. They show up in a lot of problems.

5 0
3 years ago
3 x + 5 = 11<br>Proceso:<br>• Verificación:<br>• Conjunto Solución:​
Varvara68 [4.7K]

Answer:

x=6

Step-by-step explanation:

11-5=6

6/3=2

4 0
4 years ago
What is the binomial expansion of (x + 2y)7?
borishaifa [10]
<h2>Thus, the required "option 4)"  is correct.</h2>

Step-by-step explanation:

We find,

(x+2y)^7

To find, the binomial expansion of of (x+2y)^7 = ?

We know that,

(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n

∴ (x+2y)^7

Here, n = 7, x = x and y = 2y

(x+2y)^7= ^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

∴ The binomial expansion of of (x+2y)^7

=x^7+14x^{6}y+84x^{5}y^2+280x^{4}y^3+560x^{3}y^4+672x^{2}y^5+448xy^6+128y^7

Thus, the required "option 4)"  is correct.

7 0
3 years ago
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