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3 years ago

A number r divided by 82

Mathematics

1 answer:

Natalija [7]3 years ago

6 0

Answer:

574 is a number that can be divided by 82

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Write 2, 330, 000 in scientific notation?

Genrish500 [490]

Answer:

2.33 × 10^6

Step-by-step explanation:

I just used a calculator, to be honest. It was super simple.

2.33 * 10^6

2.33 * (10*10*10*10*10*10)

which then equals 2,330,000

6 0

3 years ago

If you could help I would really appreciate it, but if not that’s fine. Thank you.

Svetradugi [14.3K]

Since 4 is between 2 & 5 you input it into the middle equation.

x=4

so the answer is 4!

7 0

3 years ago

How do you solve this? x - 2y = 4

valentina_108 [34]

If you want to solve for x, then
add 2y to both sides
x=2y+4
if want to solve for y
minus x both sides and divide by -2
x-2y=4
-2y=-x+4
y=1/2x-2

5 0

3 years ago

Find the equation of a line parallel to x = 7 and passing through the point (2, -5)

photoshop1234 [79]

The answer is: " x = 2 " .
____________________________________

5 0

3 years ago

A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%

IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

$P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18$

a) P(firm will make at least one hire)

$P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32$

Also,

$P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4$

$\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9$

b) expected value and the standard deviation of the number of hires.

$E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58$

$E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89$

7 0

3 years ago