Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
Step-by-step explanation:
B
That is sudoku, a game that I am really good at. first off the square on the left in the middle is messed up, because on the square above it there is a 5 where it would make the 5 in the middle left square incorrect. So you have to erase the 5 in the square on the middle left. Then if you can do sudoku, you could do the rest.
hope I helped!
