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Scorpion4ik [409]

3 years ago

11

The product of twenty-one negative integers is negative. True False

2 answers:

Shkiper50 [21]3 years ago

5 0

Answer: TRUE:
_____________________
It is TRUE that the product of 21 (twenty-one) negative integer is a negative number; because you are multiplying an ODD NUMBER of NEGATIVE INTEGERS.
________________________

kobusy [5.1K]3 years ago

5 0

The correct answer for the given statement above would be TRUE. It is true that the product of twenty-one <span>negative integers is negative. Analyze this. If you multiply 2 negative integers, it gives you a positive integer. So, every 2 negative integers you multiply, the product will always be positive, and since the given is 21 negative integers, this would also give you a negative result. Hope this answer helps.</span>

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Rewrite 4/7 and 3/5 so they have common denominator

Vladimir [108]

20/35 and 21/35. The common denominator is 35.

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2 years ago

What is 11/9/18 as a mixed number in simplest form.

12345 [234]

The answer is 22 because in order to divide fractions (in this case we would have 11 as a fraction), you need to multiply one fraction by the reciprocal of the other fraction (the flipped form of a fraction).

To find this, we would do $\frac{11}{1}$ * $\frac{9}{18}$ .

This would come to be $\frac{198}{9}$ , and when simplified by dividing the numerator and denominator by 9, you get 22.

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3 years ago

Which expression represents the distance between 4.7 and −11.2 on the number line?

Cerrena [4.2K]

Answer:

4.7 - ( -11.2)

Step-by-step explanation:

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2 years ago

segment MN is shown. Point M is located at (7,6). Point N is located at (7,-4) What is the midpoint segment of MN

Luda [366]

Answer:

The midpoint of MN is <u>(7,1)</u>

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6 0

2 years ago

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

4 0

3 years ago

Read 2 more answers