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3 years ago

The product of twenty-one negative integers is negative. True False

2 answers:

5 0

Answer: TRUE:
_____________________
It is TRUE that the product of 21 (twenty-one) negative integer is a negative number; because you are multiplying an ODD NUMBER of NEGATIVE INTEGERS.
________________________

kobusy [5.1K]3 years ago

5 0

The correct answer for the given statement above would be TRUE. It is true that the product of twenty-one <span>negative integers is negative. Analyze this. If you multiply 2 negative integers, it gives you a positive integer. So, every 2 negative integers you multiply, the product will always be positive, and since the given is 21 negative integers, this would also give you a negative result. Hope this answer helps.</span>

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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

Jim is putting money into a savings account. He starts with $350 in the savings account, and each week he adds $60.

lukranit [14]

Answer:

S= 350+60w

Step-by-step explanation:

4 0

3 years ago

How many quarts of pure antifreeze must be added to 5 quarts of a 40% antifreeze solution to obtain a 50% antifreeze solution

GarryVolchara [31]

Answer:

2 quarts of 100% antifreeze.

Step-by-step explanation:

5 quarts/ .40 * x/ 1

.40x= 5

x=2

6 0

3 years ago

What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?

Fantom [35]

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is $M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

Let ( $x_1,y_1$ ) be the point (3.5, 2.2) and ( $x_2, y_2$ ) be the point (1.5, -4.8)

substituting the points in the formula

$M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)$

$=\left(\frac{5}{2}, \frac{-2.6}{2}\right)$

$=\left(2.5,-1.3\right)$

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

8 0

3 years ago

What is the theoretical probability that the dial will land on the number 5? Enter your answer in all forms

Sedbober [7]

Answer:

1/3

Step-by-step explanation:

There are <u>four</u> 5's on the dial out of 12 possible stops

4/12 = 1/3 theoretical

5 0

2 years ago

Read 2 more answers