Answer:
16
This seems to have been miswritten. So I went ahead and just put it as 50, 3 and 2
Explanation:
Okay, so Jack started with 50 chocolates and ended with 2.
The simple way to calculate it would be by realizing that Jack only distributed 48 chocolates. We can find how many times 3 fits into 48 by dividing 48÷3=16.
Using algebra, we substitute the value we want to find with x. Here what we want to find is the number of friends that were at Jack's party.
We know that he started with 50 chocolates, then distributed 3× the number of friends present (which is x).
We write that down as 50−3x
(It's minus because when chocolates are distributed, Jack is taking away from what he has.)
We know that after this, there were only 2 chocolates left, so it's
50−3x=2
Then we proceed by moving all the numbers to the right until only x is left:
<span>−3x=2−50</span>
<span>−3x=−48</span>
<span>x=<span><span>−48</span><span>−3</span></span></span>
<span>x=16</span>
Conclusion: The number of people that attended the party was 16.
Answer:
$549
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year,
then, solving our equation
I = 3050 × 0.06 × 3 = 549
I = $ 549.00
The simple interest accumulated
on a principal of $ 3,050.00
at a rate of 6% per year
for 3 years is $ 549.00.
Answer:
d
Step-by-step explanation:
you subsutute the answer x equalys for x
Two common tangents occur when two circles intersect each other at two points.
<h3>How to illustrate the information?</h3>
It should be noted that two common tangents are also referred to as transverse common tangents.
In this case, two common tangents occur when two circles intersect each other at two points.
The diagram is attached.
Learn more about tangent on:
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For a better understanding of the solution provided here please go through the diagram in the file that has been attached.
As can be clearly seen from the question and the graph, the area is bounded by a straight line
which passes through the origin, the y axis and the horizontal line
.
As we can see from the graph, this is a right triangle. To find the point of intersection of the horizontal line y=6 and the line
, we will have to equate the two as:

Therefore, 
Thus, 
Hence the point of intersection is (12,6) which is depicted on the graph too.
As this is a case of a simple right triangle, the area of the bounded region will thus be:

Let the base be the y=6 line whose length is 12 and let height be the y axis whose length is 6, thus, the area will be:
squared units.