Answer:
the answer for the first part is 260
the equation is n+8
Step-by-step explanation:
all you need to do is take the starting number witch is 13 then you add 8 and then take that number and add 8 so thats why the equation is n+8 n equaling the starting number and 8 equaling to the reoccurring number.
Answer:
7
because 10.8 - 3.8 =7
therefore the answer is 7
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
Answer: a. 4,700 mh
Step-by-step explanation:
Assuming:
The only option that is correct is a. 4,700 mh, let's prove it with the following conversion:
Answer:
1278 R2
Step-by-step explanation:
Use long division.
6, 392 divided by 5
= 1278 R2
The answer is 1,278, with a remainder of 2.
Hope this helps :)
