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postnew [5]
3 years ago
14

Is this right? im very confused

Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

yes!

Step-by-step explanation:

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Pls does anyone know the answer??
galina1969 [7]

Answer:

The on  the bottom is right.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP Write the equation of a line perpendicular to y=2x−3 and goes through the point (4,-1).
dmitriy555 [2]
So for something to be perpendicular the gradient must be the negative reciprocal of your original line so your original gradient is 2 so your new gradient will be -1/2. Then you have y = -1/2 x + c . Now you substitute this into the point (4,-1) to get -1 = -1/2 x 4 + c and -1/2 x 4 = -2 so you have -1 = -2 + c so c = 1 so then you put the equation together to get y = -1/2 x + 1
Hope this helps :))
6 0
4 years ago
in a tidal river, the time between high and low tide is 7.6 hours. At high tide the depth of water is 17.2 feet, while at low ti
Lady_Fox [76]
Alright, so the difference between tidal heights is 12.6 ft. right? For every integer cos(x) is multiplied, say a*cos(x) the amplitude doubles. So then, (1/2)=(n/12.6) will gives us a value for a that will match the differences in tidal height. a=6.3. Now let's say that 2pi will give us a full cycle from high to low back to high again. If 12:00 noon is our high, it takes 15.2hrs to complete a cycle back to high again. 2pi = 6.28 roughly, and we know that is less than our midpoint in a whole cycle, 7.6 hrs. Also, for every value k>1 in cos(kx), this increases the frequency of waves in a given period. So it seems that we need a value of k less than 1. So we can lower the frequency to match the cycle we are looking for, which is to come back to 17.7 ft by 15.2hrs. So to find our value k we divide 2pi by 15.2. This is 0.41. We do it that way based on the ratio for the standard period to what we need, which is a number that can get us to 15.2. So far we have f(t) = 6.3cos(0.41x). Now the problem we have now is that we are not at our height for max, nor our min, even though our wave matches the difference between them, we are between 6.3 and -6.3 so far. so for every value of c in cos(x)+c, this adds to the height cos starts on the y-axis. Since we are at 6.3 already, all we need to do is subtract 6.3 from 17.6 to get c. So C is 11.3 and our final equation is f(t)=6.3cos(0.41x)+11.3. This gives our tides in 15.2 hr periods, starting at 12 noon = x=0, with extremes at intervals of 7.6 hours. Let me know if you have any more questions about it, it's kind of rough to explain. We transformed by f(t)=a*cos(kx)+c altogether, but I thought it might help to separate each value independently.
4 0
3 years ago
Read 2 more answers
Several students made comments about this image. A triangle has angles B, C, D. The exterior angle to angle B is A. Which commen
professor190 [17]

A Comment "If i know the measures of angles C and B, I can find the measures of A and D" is TRUE

Explanation :

If we know angles C and B we can find angles A and D as,

As from figure we know

                     A+B = 180°

∴                     A = 180° - B                           ... we know B so we get A

Also,

                   B+C+D = 180°                          ... as BCD is a triangle

∴                           D = 180° - (B+C)              ... we know B and C so we get D    

8 0
3 years ago
Read 2 more answers
WHAT ARE THESE ALSO EXPLAIN HOW YOU DID ITT DUE SOOOON
Zepler [3.9K]

Answer:

down below

Step-by-step explanation:

4. 5/11 x 2/2 = 10/22: yes

5. 36/4 = 9 but 2x9 = 18 not 20: no

7 0
3 years ago
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