The sum of the arithmetic sequence given by
<span>an = 0.05(n – 1) – 0.6
will be given by:
a1=0.05(1-1)-0.6=-0.6
a2=0.05(2-1)-0.6=-0.55
a3=0.05(3-1)-0.6=-0.5
a4=0.05(4-1)-0.6=-0.45
a5=0.05(5-1)-0.6=-0.4
thus the summation will be:
-0.6+(-0.55)+(-0.5)+(-0.45)+(-0.4)
=-2.5
hence
S5=-2.5</span>
<u>Answer:</u>
The correct answer option is
.
<u>Step-by-step explanation:</u>
We are given the following expression and we are to evaluate it when
and
:
![[\frac{3^2a^{-2}}{3a^{-1}} ]^k](https://tex.z-dn.net/?f=%5B%5Cfrac%7B3%5E2a%5E%7B-2%7D%7D%7B3a%5E%7B-1%7D%7D%20%5D%5Ek)
Substituting the given values of
and
to get:
![[\frac{3^2(5)^{-2}}{3(5)^{-1}} ]^{-2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B3%5E2%285%29%5E%7B-2%7D%7D%7B3%285%29%5E%7B-1%7D%7D%20%5D%5E%7B-2%7D)






Can you show a better picture?
Answer:
As a fraction it must be 1/3
The answer is 447 because you got to add 35 plus 410