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3 years ago

On July 1, 2021 Sikie Shoe Manufacturing Co. issued 45,000 common shares for cash at a Market price of $25

Mathematics

1 answer:

Gnom [1K]3 years ago

5 0

Answer:

$1125000

Step-by-step explanation:

45,000 x 25 = 1125000

Since the question didn't specify what values to calculate, I will assume that it is how much money was issued in total.

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Josh works for MooMoo Milkshakes. The company wants to know what milkshake flavor is the most popular. Today, he surveyed every

miv72 [106K]

The answer is D, there is no bias as Josh used random sampling.

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3 years ago

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I will venmo if someone can please help me

shutvik [7]

Answer: 14.967

Step-by-step explanation:

Use Pythagorean Theorem to find the missing length.

a² + b² = c²

x² + 10² = 18²

x² + 100 = 324 [Subtract 100 from both side]

x²= 224

√x² = √224 [solve the square root from both sides]

x ≈ 14.967

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3 years ago

A store buys shirts from

Anna007 [38]

Answer:

1.25*12=15

Step-by-step explanation:

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3 years ago

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

3 years ago

Each week our school’s team travels to other schools for competitions. Today the five members of the gymnastics team and seven w

Aliun [14]

Answer: The answer is 9.

Step-by-step explanation: Given that five members of gymnastics team and 7 members of weight lifting team are travelling in two vans to the rival school for competition. We are to find the number of ways in which they can ride in two vans such that no van contains more than eight passengers and there is at least one member of each team in each van.

Let 'g' and 'w' denote a member of gymnastics team and weight lifting team respectively.

Then, the possibilities are

For 1 g, we can choose 3w, 4w, 5w, 6w.

For 2g, we can choose 2w, 3w, 4w, 5w, 6w.

For 3g, we can choose 1w, 2w, 3w, 4w, 5w.

For 4g, we can choose, 1w, 2w, 3w, 4w.

Therefore, there are (4 + 5 + 5 + 4) = 18 ways.

Since, here the position of the vans does not matter, so the options are double here. Hence, we must divide it by 2.

Thus, the total number of ways = 9.

4 0

3 years ago