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3 years ago

10

Taylor uses 645.6 gallons of water in 7 days. Suppose he uses the same amount of water each day. About how much water does taylo

r use each day?

2 answers:

ahrayia [7]3 years ago

4 0

About 92.2 gallons a day

jenyasd209 [6]3 years ago

3 0

<span>92.23 Gallons per day. Because you divide 645.6 by 7, so that you can calculate the daily usage. :) </span>

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Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans

Valentin [98]

Answer:

1. $2r+1.6b=10$

2. $r=5-0.8b$

3. $b=6.25-1.25r$

Step-by-step explanation:

<h3> The complete exercise is: "Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans and rice for a potluck dinner. Let b be the number of pounds of beans Lin buys and r be the number of pounds of rice she buys when she spends all her money on this meal.</h3><h3>1. Write an equation relating the two variables.</h3><h3>2. Rearrange the equation so "b" is the independent variable.</h3><h3>3. Rearrange the equation so "r" is the independent variable."</h3><h3 />

1. According to the information exercise given in the exercise, the cost per pounds of brown rice is $2. Since "r" represents the number of pounds of rice Lin buys, the total cost of the brown rice she buys can be represented with this expression:

$2r$

The beans cost $1.60 per pound. Since "b" represents the number of pounds of beans Lin buys, the total cost of beans she buys can be represented as:

$1.6b$

Knowing that she spends $10, you can write the following equation:

$2r+1.6b=10$

2. In order to rearrange the equation so "b" is the independent variable, you need to solve for "r":

$2r+1.6b=10\\\\2r=10-1.6b\\\\r=\frac{10-1.6b}{2} \\\\r=5-0.8b$

3. To rearrange the equation so "r" is the independent variable, you must solve for "b". You get:

$2r+1.6b=10\\\\1.6b=10-2r\\\\b=\frac{10-2r}{1.6}\\\\b=6.25-1.25r$

7 0

3 years ago

For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr

pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables $X_i$ with the following distribution:

$X_i Bin (1,p) = Be(p)$ bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

$Z = \sum_{i=1}^N X_i$

From the info given we know that $N \sim Bin (M,q)$

We need to proof that $Z \sim Bin (M, pq)$ by the definition of binomial random variable then we need to show that:

$E(Z) = Mpq$

$Var (Z) = Mpq(1-pq)$

The deduction is based on the definition of independent random variables, we can do this:

$E(Z) = E(N) E(X) = Mq (p)= Mpq$

And for the variance of Z we can do this:

$Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2$

$Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2$

And if we take common factor $Mpq$ we got:

$Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]$

And as we can see then we can conclude that $Z \sim Bin (M, pq)$

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3 years ago

What is the answer to this

photoshop1234 [79]

Answer:

true

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which expressions represent the difference of exactly two expressions? choose 3 answers.

Kitty [74]

Answer:

A,C and D

in a 6(x + 7)-2

= (6x + 42)-2

c) 4f-2g

d) 3xyz-10

these three options I think

Hope it helps

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3 years ago

With a fair die, the probability of rolling any number 1 through 6 is the same.

yaroslaw [1]

The probability of all possible outcomes is always 1, meaning 100%.

In this case the probability of rolling a 1,2,3,4,5, or 6 is:

1/6+1/6+1/6+1/6+1/6+1/6

6(1/6)

6/6

1

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3 years ago

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