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strojnjashka [21]
3 years ago
9

Apply the distributive property to factor out the greatest common factor 60m-40=

Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0

Answer:

The greatest common factor is 20

Step-by-step explanation:

Rewrite 40 as 20*2

Rewrite 60 as 20*3

=20*3m-20*2

Factor out common term 20;

20(3m-2)

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docker41 [41]

Answer:

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Read 2 more answers
(2n-9)-(-2.4n+4) Please help!
Furkat [3]

Answer: =4.4n-13

Step-by-step explanation:

Let's simplify step-by-step.

2n−9−(−2.4n+4)

Distribute the Negative Sign:

=2n−9+−1(−2.4n+4)

=2n+−9+−1(−2.4n)+(−1)(4)

=2n+−9+2.4n+−4

Combine Like Terms:

=2n+−9+2.4n+−4

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4 0
3 years ago
The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?
Nataly_w [17]

Answer:

||\overrightarrow{v}||\approx14.64

Step-by-step explanation:

The magnitude of a vector \displaystyle \overrightarrow{v}=\langle x,y\rangle is ||\overrightarrow{v}||=\sqrt{x^2+y^2}, which essentially describes the length of the vector itself between the initial and terminal points:

||\overrightarrow{v}||=\sqrt{x^2+y^2}\\\\||\overrightarrow{v}||=\sqrt{(10.5)^2+(10.2)^2}\\\\||\overrightarrow{v}||=\sqrt{110.25+104.04}\\\\||\overrightarrow{v}||=\sqrt{214.29}\\\\||\overrightarrow{v}||\approx14.64

6 0
2 years ago
Determine whether each of the binary relation R defined on the given sets A is reflexive, symmetric, antisymmetric, or transitiv
ki77a [65]

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

a)

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

b)

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

c)

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

6 0
3 years ago
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