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4 years ago

35+14 distributive property

Mathematics

2 answers:

Lera25 [3.4K]4 years ago

5 0

Answer:

7(2)+7(5) {using distributive property}

14+35 {7 multiplied by 2 gives 14 and 7 multiplied by 5 gives 35}

49 {therefore 35+14 gives 49}

Step-by-step explanation:

Your answer is 49

Hope this helps :)

max2010maxim [7]4 years ago

4 0

The answer is 49 I hope you like it

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0= -16t^2 + 98 solve for t round to the nearest tenth if needed

Lunna [17]

Answer:

t = 7 • ± √2 = ± 9.8995

Step-by-step explanation:

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3 years ago

Please answer both A and B

Oliga [24]

Answer:

A is that they both are triangles and they both have right angles

Step-by-step explanation:

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3 years ago

1. What is the simplified form of (x-3)/(x^2+x-12)• (x+4)/(x^2+8x+16) ?. . 2.What is the simplified form of (x+1)/(x^2+x-6) divi

WARRIOR [948]

To simplify an equation like this you must factor out the binomial equation and proceed in cancellation of the same equation.
1. (x-3)/(x-3)(x-4) answer is (x-4)
2.the simplified form after the cancellation is 1/(x-2)(x+4)
3.y+x
4.2x-1/x
I hope i answered your questions correctly

7 0

3 years ago

The product of nine and a number is added to six the result is 24 what is the number

Andru [333]

Hello!

We can make an equation based on what we know

The product of 9 and a number is

9 * x

Added to six

9 * x + 6

Gives the result of 24

9 * x + 6 = 24

Now you solve it algebraically

Subtract 6 from both sides

9 * x = 18

Divide both sides by 9

x = 2

The answer is 2

Hope this helps!

8 0

3 years ago

The American Veterinary Association claims that the annual cost of medical care for dogs averages $100 with a standard deviation

Taya2010 [7]

Answer:

The probability that the cost for someone's dog is higher than for the cat is 33.2%.

Step-by-step explanation:

With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.

To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).

Then we have to calculate z, and look up in a standarized normal distribution table.

Calculate z:

$z=\frac{X-\mu}{\sigma}=\frac{0-(-20)}{46}=\frac{20}{46}= 0.4348$

The probability of the difference being higher than 0, we have:

$P(d>0)=P(z>0.4348)=0.33185$

We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.

8 0

3 years ago