5 The slope of EF is Which segments are perpendicular to EF? Select each correct answer.
1 answer:
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Hey John
Let's start solving #1
x/4 = 3.5/28
Cross multiply
(x)(28) = (3.5)(4)
28x = 14
Divide both sides by 28
28x/28 = 14/28
x = 1/2
Next, let's solve the second one
Simplifies to:
Cross multiply
(105x + 75)(5) = (28)(50x)
525x + 375 = 1400x
Subtract 1400x to both sides
525x + 375 - 1400x = 1400x - 1400x
-875x + 375 = 0
Then subtract 375 from both sides
-875x + 375 - 375 = 0 - 375
-875x = -375
To find x, divide both sides by -875
-875x/-875 = -375/-875
x = 3/7
Let me know if you have questions about the answer.
Best of luck with your studies!
Let's start solving #1
x/4 = 3.5/28
Cross multiply
(x)(28) = (3.5)(4)
28x = 14
Divide both sides by 28
28x/28 = 14/28
x = 1/2
Next, let's solve the second one
Simplifies to:
Cross multiply
(105x + 75)(5) = (28)(50x)
525x + 375 = 1400x
Subtract 1400x to both sides
525x + 375 - 1400x = 1400x - 1400x
-875x + 375 = 0
Then subtract 375 from both sides
-875x + 375 - 375 = 0 - 375
-875x = -375
To find x, divide both sides by -875
-875x/-875 = -375/-875
x = 3/7
Let me know if you have questions about the answer.
Best of luck with your studies!