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bagirrra123 [75]
3 years ago
10

Huey has a fish tank that measures 5 feet long by 2 feet wide and 2 feet tall . The volume of the tank.

Mathematics
1 answer:
iris [78.8K]3 years ago
3 0
This is a simple problem

First, take common sense and apply it here. The problem doesn't specifically tell you what the shape ACTUALLY is, but we can also apply what we know about geometry here, as well as what we know in general. Fish tanks most commonly come in 2 shapes: Square's and Rectangles. Fish tanks are what we call "3D" objects (meaning it's just not flat like a piece of paper", and the shapes are known as "Cubes and Rectangular Prisms".

Well, we know that squares/cubes have to have even sides. The problem states the tank is 5(l) by 2(w) by 2(h). This means it CAN'T be a cube, thus meaning it's a rectangular prism.

Now, to calculate volume, we have to know the formula. For this, the formula for volume is as follows: V=lwh
This means Volume=Length*Width*Height

So, do replace the words with what you know you already have. Let's make a list:
Length=5
Width=2
Height=2

V=lwh-----V=5*2*2

Now, work it out. 5*2=10*2=20, Left to right

Your answer here is V=20

~Hope this helps!
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What is the equivalent decimal form for<br> 2/40?
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Answer:

decimal form: 0.05

Step-by-step explanation:

To find decimals divide them, so 2 divided by 40 is 0.05.

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Read 2 more answers
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
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Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

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3 years ago
Pls help me. i need it
Juli2301 [7.4K]

Answer:

option 2 is correct

Step-by-step explanation:

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