Answer:
The three questions about the given triangle has been answered below.
Step-by-step explanation:
We are given a right angled triangle whose sides are of length 20, 21 and 29.
<u>(1)</u> sin(B) = 
= 
= 0.72
<u>(2)</u> sin(A) = 
sin(A) = 0.689
∠CAB = 
∠CAB = 43.551°
<u>(3)</u> We suppose that cosA < sinA and we haveto find which all angles will satisfy this condition.For this the angle A should be greater than 45°.
From the given options the angles that satisfy this are 55 , 66 and 75.
45 is not included as then sinA = cosA and that condition is not there.
Answer:
It's 1/2 I found this out by subtracting 3/4 - 1/3= 5/12 and if you put that into a decimal it would be .41. So that 1/4= .25 and 1/2= .50. You could figure out that it’s closed to 1/2.
B² = 8b + 84
b² - 8b - 84 = 0
b = <u>-(-8) +/- √((8)² - 4(1)(-84))</u>
2(1)<u>
</u>b = <u>8 +/- √(64 + 336)</u>
2
b = <u>8 +/- √(400)
</u> 2<u>
</u>b = <u>8 +/- 20
</u> 2
b = 4 <u>+</u> 10
b = 4 + 10 b = 4 - 10
b = 14 b = -6
<u />
The answer is 5.5 m.
Cube
Volume = length x width x height
Since the length, width and the height are the same in cube, the formula can be:
Volume = length^3
Let x metres be the side length of the cube.
166 = x^3
x = ∛166
x = 5.495864.....
x = 5.5 (nearest tenth)
(4^9)^5 is equal to 4^45. You multiply 9 and 5 to get 45.
