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jeka94
3 years ago
5

What is the solution of the equation (x – 5)2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

Mathematics
1 answer:
blondinia [14]3 years ago
7 0

Answer:

Option 2 -  x=\frac{7\pm3\sqrt{3}i}{2}

Step-by-step explanation:

Given : Equation (x-5)^2+3(x-5)+9=0

To find : What is the solution of the equation ?

Solution :

Using substitution method,

Let y=x-5

y^2+3y+9=0

Using quadratic formula, x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, a=1, b=3 and c=9

y=\frac{-3\pm\sqrt{3^2-4(1)(9)}}{2(1)}

y=\frac{-3\pm\sqrt{-27}}{2}

y=\frac{-3\pm3\sqrt{3}i}{2}

Substitute back,

x=\frac{-3\pm3\sqrt{3}i}{2}+5

x=\frac{-3\pm3\sqrt{3}i+10}{2}

x=\frac{7\pm3\sqrt{3}i}{2}

Therefore, option 2 is correct.

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3 years ago
The radius of circle O is 28, and OC =9. What is the length of AB?
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The answer:
the complement of the question proposed one of the choices given beneath:
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consider OCB
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the problem is how to find the length of CA, for that C is a midpoint of segment AB, so AC=BC

BC can be found by using pythagorean theorem
OB²= OC² + CB²,  this implies CB² = OB² - OC²

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CB=26.51, since CB= AC, so  AC=CB= 26.51

finally the <span>the length of AB is AB = 2 x CB = 2x AC= 2x 26.51= 53.0
</span>
the answer is b) 53.0

7 0
3 years ago
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yuradex [85]

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